1. What is the total mass of the items in the wheel barrow?
9300g
2. What’s the mass of items, in kg, left in the barrow?
4.9kg
Answer:
0.95988 (Accuracy of the test )
Step-by-step explanation:
To determine the accuracy of this test we have to list out the given values
Prevalence rate of the disease = 0.3% = 0.003
sensitivity rate of the disease = 92% = 0.92
specificity rate for the test = 96% = 0.96
The accuracy of the test can be found using this equation
Accuracy = sensitivity * prevalence + specificity ( 1 - prevalence )
= 0.92 * 0.003 + 0.96 ( 1 - 0.003 )
= 0.00276 + 0.95712
= 0.95988
Answer:
9)x=11 y=3
11)x=18 y=5
Step-by-step explanation:
9) 9x+25=13x+19 13x-19+17y+5=180
9x+44=13x 129+17y=180
44=4x 17y=51
11=x y=3
11) 49+3x=7x-23 3x=11y-1
The answer in this question is A, D and E, we might conclude if a random sample of 36 time interval between eruption has a mean longer that 104 minutes, I can conclude that the population means may be greater than 91 and the probability mean must be more that 91, since the probability is low and also the population mean is 91, and this is an example of a typical sampling result.
Answer:
<em>0.5306</em>
<em>0.5694</em>
Step-by-step explanation:
USing the formuls for calculating the confidence interval for the population proportion;
CI = p±Z*√[p(1-p)/n]
p is the percentage proportion of the population 55%
Z is the z-score at 99% confidence interval = 2.576
n is the sample size = 1079
CI = 0.55 ± 2.576*[0.55(1-0.55)/√1079]
CI = 0.55 ± 2.576*[0.55(0.45)/√1079]
CI = 0.55 ± 2.576*[0.2475/√1079]
CI = 0.55 ± 2.576*[0.2475/32.85]
CI = 0.55 ± 2.576*[0.00753]
CI = 0.55 ±0.0194
CI =(0.55-0.0194, 0.55+0.0194)
CI = (0.5306, 0.5694)
<em>Hence, a 99% confidence interval of the proportion of the population that will support such a law is 0.5306</em><em>0.5694</em>
