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2 years ago

11

At the video game store, they were having a sale. There was a pack of 3 games for $45.96. If the games were all the same price,

what was the cost of each game in the pack?

1 answer:

lesya692 [45]2 years ago

5 0

Answer:

$15.32 per game

Step-by-step explanation:

45.96/3 = 15.32

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WILL GIVE BRAINLIEST! whats the unit rate of the equation(HAVE TO SHOW HOW YOU GOT ANSWER)

Vika [28.1K]

Answer:

32

Step-by-step explanation: OH NO MY SEXUALITY ITS BROCKEN

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2 years ago

Are the functions inverse of each other?<br><br> f(x)=5x^2+3, g(x)sqrt x-3/5

luda_lava [24]

Answer:

No.

Step-by-step explanation:

Plugging in g(x) into f(x), you don't get x. g(x) would need to be = $\sqrt{x\frac{-3}{5} }$

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2 years ago

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Suppose you just received a shipment of nine televisions. Three of the televisions are defective. If two televisions are randoml

Temka [501]

<h2>Answer:</h2>

a)

The probability that both televisions work is: 0.42

b)

The probability at least one of the two televisions does not work is:

0.5833

<h2>Step-by-step explanation:</h2>

There are a total of 9 televisions.

It is given that:

Three of the televisions are defective.

This means that the number of televisions which are non-defective are:

9-3=6

a)

The probability that both televisions work is calculated by:

$=\dfrac{6_C_2}{9_C_2}$

( Since 6 televisions are in working conditions and out of these 6 2 are to be selected.

and the total outcome is the selection of 2 televisions from a total of 9 televisions)

Hence, we get:

$=\dfrac{\dfrac{6!}{2!\times (6-2)!}}{\dfrac{9!}{2!\times (9-2)!}}\\\\\\=\dfrac{\dfrac{6!}{2!\times 4!}}{\dfrac{9!}{2!\times 7!}}\\\\\\=\dfrac{5}{12}\\\\\\=0.42$

b)

The probability at least one of the two televisions does not work:

Is equal to the probability that one does not work+probability both do not work.

Probability one does not work is calculated by:

$=\dfrac{3_C_1\times 6_C_1}{9_C_2}\\\\\\=\dfrac{\dfrac{3!}{1!\times (3-1)!}\times \dfrac{6!}{1!\times (6-1)!}}{\dfrac{9!}{2!\times (9-2)!}}\\\\\\=\dfrac{3\times 6}{36}\\\\\\=\dfrac{1}{2}\\\\\\=0.5$

and the probability both do not work is:

$=\dfrac{3_C_2}{9_C_2}\\\\\\=\dfrac{1}{12}\\\\\\=0.0833$

Hence, Probability that atleast does not work is:

0.5+0.0833=0.5833

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3 years ago

Will give brainliest answer

ArbitrLikvidat [17]

Answer:

180°

Step-by-step explanation:

Connecting any point of original figure with the same of the image

For example point C with C'

The line goes through the origin (0, 0)

<u>And the coordinates changed as:</u>

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2 years ago

25.6% of what # is 21.12

laila [671]

To solve this problem, we are going to use the percent proportion, a/b = p/100, where a is the part of a number b, the whole, and p is the percentage out of 100.
When we fill in our known integers into this equation, we get

21.12 / b = 25.6 / 100

Next, to simplify this equation, we should use cross products (means - extremes products theorem). This means multiplying the numerator of one fraction and the denominator of the other fraction and setting them equal to one another.

21.12(100)=25.6(b)

When we multiply, you get

2112 = 25.6b

Finally, we divide both sides by 25.6, to get our variable b, alone, and without a coefficient.

82.5 = b

Therefore, 25.6% of the number 82.5 is 21.12.

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2 years ago

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