Answer:
the slope of both lines are the same.
Step-by-step explanation:
Given the following segment of the Quadrilateral EFGH on a coordinate Segment FG is on the line 3x − y = −2,
segment EH is on the 3x − y = −6.
To determine their relationship, we can find the slope of the lines
For line FG: 3x - y = -2
Rewrite in standard form y = mx+c
-y = -3x - 2
Multiply through by-1
y = 3x + 2
Compare
mx = 3x
m = 3
The slope of the line segment FG is 3
For line EH: 3x - y = -6
Rewrite in standard form y = mx+c
-y = -3x - 6
Multiply through by-1
y = 3x + 6
Compare
mx = 3x
m = 3
The slope of the line segment EH is 3
Hence the statement that proves their relationship is that the slope of both lines are the same.
If the perimeter is 16, the side length is 4 units.
To find the area of the shaded sections, you will use the fractional part that each section represents and multiply that fraction by the total area of the square.
Area of DEA is 1/4 of 16 square Units (4 x 4).
1/4 x 16 = 4 square units
Area of EFB is 1/8 of 16 square units.
1/8 x 16 = 2 square units
4 square units +2 square units equals 6 square units.
The area of the shaded region is 6 square units.
Plug in the dimensions to the formula given using a handy dandy calculator for both problems.
1. The diameter of the bottom of the cone is 4 so the radius (half that) is 2. Volume = 1/3 * pi * (2)² * 6
= 1/3 * pi * 4 * 6
= 1/3 * pi * 24
= 8 * pi
≈ 25.1327 cm³
2. They give you all you need, the radius.
Volume = 4/3 * pi * (6)³
= 4/3 * pi * 216
= 288 * pi
≈ 904.7787 in³
The interpretation of the solution is that there are 15 true/false questions and 5 multiple choice questions.
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