<span>EP (potential energy) = mgy -> (59)(9.8)(-5) = -2,891
EP + EK (kinetic energy) = 0; but rearranging it for EK makes it EK = -EP, such that EK = 2891 when plugged in.
EK = 0.5mv^2, but can also be v = sqrt(2EK/m).
Plugging that in for sqrt((2 * 2891)/59), we get 9.9 m/s^2 with respect to significant figures.</span>
Answer:
Part a)
Part b)
Part c)
Speed is more than the required speed so it will reach the top
Explanation:
Part a)
As we know that there is no frictional force while block is moving on horizontal plane
so we can use energy conservation on the block
Part b)
If the track has average frictional force of 7 N then work done by friction while block slides up is given as
work done against gravity is given as
Now by work energy equation we have
Part c)
now minimum speed required at the top is such that the normal force must be zero
so here we got speed more than the required speed so it will reach the top
W=mgh W=(20)(9.8)(1) w=196J
Answer:
Kinetic Energy.
Explanation:
The movement of a roller coaster is accomplished by the conversion of potential energy to kinetic energy. The roller coaster cars gain potential energy as they are pulled to the top of the first hill. As the cars descend the potential energy is converted to kinetic energy.
The Answer is B : The water particles become locked in place.