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2 years ago

Which prefix would appear in the IUPAC name for a covalent compound that has four atoms of a single element?

1 answer:

4 0

The correct prefix is ‘tetra’. You can remember this because in Tetris (the game) you always get a block that consists out of 4 small squares arranged differently.

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If Junes mother had 3 children July August who is the third child

Molodets [167]

June is the third child

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2 years ago

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What do ALL states of matter have in common?

VLD [36.1K]

Answer:

The common thing among the three states of matter is - They are made up of small tiny particles. They have a particular mass and can occupy space . This three states have volume in it . The atoms of this three states have force of attractions between them .

Explanation:

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2 years ago

How many atoms of hydrogen combine with one carbon atom to form methane

bonufazy [111]

Answer:four hydrogen atoms

Explanation:

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2 years ago

What is the volume of an 2.3 solution with 212 grams of calcium chloride dissolved in it

Travka [436]

830 mL. A 2.3 mol/L solution of CaCl2 has a volume of 830 mL

I am guessing that the concentration of your solution is 2.3 mol/L.

a) Moles of CaCl2

MM of CaCl2 = 110.98 g/mol

Moles of CaCl2 = 212 g CaCl2 x (1 mol CaCl2/110.98 g CaCl2)

= 1.910 mol CaCl2

b) Volume of solution

V = 1.910 mol CaCl2 x (1 L solution/2.3 mol CaCl2) = 0.83 L solution

= 830 mL solution

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2 years ago

When the volume of a gas is

Montano1993 [528]

Answer:

$\boxed {\boxed {\sf 232.9 \textdegree C}}$

Explanation:

This question asks us to find the temperature change given a volume change. We will use Charles's Law, which states the volume of a gas is directly proportional to the temperature. The formula is:

$\frac {V_1}{T_1}= \frac{V_2}{T_2}$

The volume of the gas starts at 250 milliliters and the temperature is 137 °C.

$\frac{250 \ mL}{137 \textdegree C}= \frac{V_2}{T_2}$

The volume of the gas is increased to 425 milliliters, but the temperature is unknown.

$\frac{250 \ mL}{137 \textdegree C}= \frac{425 \ mL}{T_2}$

We are solving for the new temperature, so we must isolate the variable T₂. First, cross multiply. Multiply the first numerator and second denominator, then multiply the first denominator and second numerator.

$250 \ mL * T_2 = 137 \textdegree C * 425 \ mL$