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2 years ago

6

A radio wave transmits 34.5 W/m2 of power per unit area. A flat surface of area A is perpendicular to the direction of propagati

on of the wave. Assuming the surface is a perfect absorber, calculate the radiation pressure on it.

1 answer:

Ira Lisetskai [31]2 years ago

7 0

Answer:

1.15*10^-7 N/m²

Explanation:

Radiation pressure is the pressure exerted on any surface, as a result of the exchange of momentum between the object and its electromagnetic field.

The formula to calculate radiation pressure on a perfect absorber is

P = s/c, where

P = radiation pressure

s = intensity of light

c = speed of light

Now, on substituting the values and plugging it into the equation, we have

P = 34.5 / 3*10^8

P = 1.15*10^-7 N/m²

therefore, radiation pressure is found to be 1.15*10^-7 N/m²

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The gage pressure of an automobile tire is measured to be 210kPa before a trip and 220kPa after the trip at a location where the

Katarina [22]

Answer:

$T_{f} = 312.348\,K\,(39.198\,K)$

Explanation:

Let assume that gas inside the automobile tire behaves as an ideal gas. Due to the absence of leakages, the number of moles remains constant during the trip. Air temperature can be found by using the following relation:

$\frac{P_{o}}{T_{o}}=\frac{P_{f}}{T_{f}}$

Final temperature is cleared with the expression:

$T_{f} = \frac{P_{f}}{P_{o}}\cdot T_{o}$

$T_{f} = \frac{220\,kPa}{210\,kPa}\cdot (298.15\,K)$

$T_{f} = 312.348\,K\,(39.198\,K)$

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2 years ago

An electric motor rated 2.5kw is used to lift bales of hay to a store in a dairy farm. A single bale has a mass of 5kg. If the s

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It can bale 13kg in 2 minutes

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1 year ago

Gretchen runs the first 4.0 km of a race at 5.0 m/s. Then a stiff wind comes up, so she runs the last 1.0 km at only 4.0 m/s.

KIM [24]

Answer:

The velocity is $v = 4.76 \ m/s$

Explanation:

From the question we are told that

The first distance is $d_1 = 4.0 \ km = 4000 \ m$

The first speed is $v_1 = 5.0 \ m/s$

The second distance is $d_2 = 1.0 \ km = 1000 \ m$

The second speed is $v_2 = 4.0 \ m/s$

Generally the time taken for first distance is

$t_1 = \frac{d_1 }{v_1 }$

$t_1 = \frac{4000}{5}$

$t_1 = 800 \ s$

The time taken for second distance is

$t_1 = \frac{d_2 }{v_2 }$

$t_1 = \frac{1000}{4}$

$t_1 = 250 \ s$

The total time is mathematically represented as

$t = t_1 + t_2$

=> $t = 800 + 250$

=> $t = 1050 \ s$

Generally the constant velocity that would let her finish at the same time is mathematically represented as

$v = \frac{d_1 + d_2}{t }$

=> $v = \frac{4000 + 1000}{1050 }$

=> $v = 4.76 \ m/s$

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Byron bought a keyless entry door lock that has the digits 0 through 9 on the keypad. He wants to choose a three-digit entry cod

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Answer:

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2 years ago

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Starting from rest, a dragster travels a straight 1/4 mi racetrack in 7.10 s with constant acceleration. What is its velocity wh

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268.6567 mph is its velocity when it crosses the finish line

d=(v1+v2 /2) x t

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v2=268.6567 mph as the speed with which the dragster crosses the finish

<h3>When acceleration is not zero, can speed remain constant?</h3>

The answer is that an accelerated motion can have a constant speed. Consider a particle travelling uniformly around a circle; it experiences acceleration since the motion's direction is changing, but it maintains a constant speed along the tangential axis throughout the motion.

Acceleration is the frequency of a change in velocity. Acceleration is a vector with magnitude and direction, much as velocity. For instance, if a car is moving in a straight path and speeding up, it is said to have forward (positive) acceleration, and if it is slowing down, it is said to have backward (negative) acceleration.

Learn more about velocity refer

brainly.com/question/24681896

#SPJ9

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