The altitude of a plane is 1200 meters. From a point on the ground, the angle of elevation of an airplane is 25º. What is the di
stance from point P to the airplane, to the nearest tenth of a meter? Explain your answer.
1 answer:
Answer:
2839.4 meters
Step-by-step explanation:
Given that:
Altitude = 1200 m
Using trigonometry :
The distance from point P to the airplane :
Using trigonometric relation :
Sin θ = opposite / hypotenus
Sin θ = altitude / x
Sin θ = 1200 m / x
Sin 25 = 1200 / x
0.4226182 = 1200 / x
x = 1200 / 0.4226182
x = 2839.4423
Distance from P to airplane = 2839.4 meters
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Step-by-step explanation:
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An nth degree<span> polynomial can have as many as n real roots.</span>
Invested at 3% = x
invested at 4% = 2x
invested at 5% = x+500
0.03x + 0.04(2x) + 0.05(x+500) = 2025
0.03x + 0.08x +0.05x +25 = 2025
0.16x = 2000
x= 12,500
4% = 2x = 12,500 * 2 = $25,000