Answer:
t = 460.52 min
Step-by-step explanation:
Here is the complete question
Consider a tank used in certain hydrodynamic experiments. After one experiment the tank contains 200 liters of a dye solution with a concentration of 1 g/liter. To prepare for the next experiment, the tank is to be rinsed with fresh water flowing in at a rate of 2 liters/min, the well-stirred solution flowing out at the same rate.Find the time that will elapse before the concentration of dye in the tank reaches 1% of its original value.
Solution
Let Q(t) represent the amount of dye at any time t. Q' represent the net rate of change of amount of dye in the tank. Q' = inflow - outflow.
inflow = 0 (since the incoming water contains no dye)
outflow = concentration × rate of water inflow
Concentration = Quantity/volume = Q/200
outflow = concentration × rate of water inflow = Q/200 g/liter × 2 liters/min = Q/100 g/min.
So, Q' = inflow - outflow = 0 - Q/100
Q' = -Q/100 This is our differential equation. We solve it as follows
Q'/Q = -1/100
∫Q'/Q = ∫-1/100
㏑Q = -t/100 + c
when t = 0, Q = 200 L × 1 g/L = 200 g
We are to find t when Q = 1% of its original value. 1% of 200 g = 0.01 × 200 = 2
㏑0.01 = -t/100
t = -100㏑0.01
t = 460.52 min
The sample standard deviation is (B) $3.16.
<h3>
What is the sample standard deviation?</h3>
- The sample standard deviation is defined as the root-mean-square of the differences between observations and the sample mean: A significant deviation is defined as two or more standard deviations from the mean.
- The lowercase Greek letter (sigma) for the population standard deviation or the Latin letter s for the sample standard deviation is most commonly used in mathematical texts and equations to represent standard deviation.
- For example, if the sample variance for a frequency distribution of hourly wages is 10 and the sample standard deviation is $3.16.
Therefore, the sample standard deviation is (B) $3.16.
Know more about sample standard deviation here:
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The complete question is given below:
If the sample variance for a frequency distribution consisting of hourly wages was computed to be 10, what is the sample standard deviation?
A. $4.67
B. $3.16
C. $1.96
D. $10.00
domain of the problem is -5 and the range is 4
Answer:
59/1
Step-by-step explanation:
0 = 0 = 0 = 0 = 0 < 54 < 56 < 59
0 is equal to 0 is equal to 0 is equal to 0 is equal to 0 is less than 54 is less than 56 is less than 59
Answer:
The median is NOT the same thing as a quartile.
The median is a measure of center.
