The annual salary of Mrs. Fredrick is $ 39397.2
<u>Solution:</u>
Given, Mrs. Frederick is paid semimonthly.
Her semi-monthly salary is $1.641.55.
Now, let us find her monthly salary first.
<em>monthly salary = 2 x semi – monthly salary </em>
So, monthly salary = 2 x 1,641.55 = $ 3283.1
Since there 12 months in a year, we obtain the annual salary as follows:
Now, the<em> annual salary = 12 x monthly salary </em>
Annual salary = 12 x 3283.1 = $ 39397.2
Hence, the annual salary of Mrs. Fredrick is $ 39397.2
This is a linear function, of the kind y = mx + b
where x is the number of visit, b is the weight when x = 0, and m is the predicted change of weight for every visit.
m = - 4 ounces / visit, which must be converted to pounds (the negative sign indicates that the change is a decrease)
1 lb = 16 ounces = 4 ounces = 0.25 lb
Then m = - 0.25 lb / visit.
Now, for x = 1, y = 126 => 126 = - 0.25(1) + b => b = 126 + 0.25 = 126.25
Then the function is y = 126.25 - 0.25x
Now round to the nearest tenth:
y = 126.3 - 0.3x
Answer: y = 126.3 - 0.3x
Answer:
w = 6.7451
x = 8.0805
Step-by-step explanation:
Find W
Tan(56) = opposite / adjacent
opposite = 10
Adjacent = w
Tan (56) = 10/w
w*Tan(56) = 10
w = 10 / tan(56)
w = 10/ 1.4826
w = 6.7451
Find x
Tan (34) = 10 / (w + x)
Tan (34) = 0.6745
(w + x) * Tan(34) = 10
w + x = 10 / tan(34)
w+ x = 10 / 0.6745
w + x = 14.826
But we found w = 6.7451
6.7451 + x = 14.826
x = 14l826 - 6.7451
x = 8.0805
Answer:
1. The total number of students in the 25-34 age group
2. 2124/19558*100= 10.9 %
Answer:
oh! thanks for points
but this is yr question or what????