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2 years ago

If u +t=5 and u – t = 2, what is the value of (u – t)(u2 – ť)? ?

Mathematics

1 answer:

raketka [301]2 years ago

5 0

Answer:

The Heaviside step function, or the unit step function, usually denoted by H or θ (but sometimes u, 1 or ), is a discontinuous function, named after Oliver Heaviside (1850–1925), whose value is zero for negative arguments and one for positive arguments.

Step-by-step explanation:

L at time ť will meet at the point z " given by the equations : z " = - ( c + U ) t ... + B ) t = ť + t " = 2y - t = tı ( 93 ) Therefore , we do not recover the value 2t = 2L / c ... if the extinction time is not zero in equation 92 , one can verify the equality t ' + t ... the mirror located on the arm covers the distance Ut ' during the time t

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Answer the question below about line 1 and line 2 shown below

aleksklad [387]

Step-by-step explanation:

commutative property of multiplication

3 * 5 means 5 + 5 + 5 which equals 15.

5 * 3 means 3 + 3 + 3 + 3 + 3 which equals 15.

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2 years ago

If m angle 2 =70, find m angle 6

rusak2 [61]

m angle 6= 210

I'm not sure about this question

5 0

1 year ago

What are the potential solutions to the equation 2ln(x+3)=0

skad [1K]

$2\ln(x+3)=0\implies \ln(x+3)^2=0\implies e^{\ln(x+3)^2}=e^0\implies (x+3)^2=1$

Expanding the left side gives

$x^2+6x+9=1\implies x^2+6x+8=0\implies (x+4)(x+2)=0$

which gives two solutions, $x=-4$ and $x=-2$ . But if $x=-4$ , then $\ln(x+3)=\ln(-1)$ , but this number isn't real, so $x=-4$ is an extraneous solution. Meanwhile if $x=-2$ , you get $\ln(-2+3)=\ln1=0$ , so this solution is correct.

"Potential solutions" might refer to both possibilities, but there is only one actual (real) solution.

4 0

2 years ago

Read 2 more answers

Jillian buys 200 shares of a company at $150 a share. She sells them at $175 a share. What is her capital gain or capital loss?

Radda [10]

200 x 150 = 30,000 to purchase
200 x 175 = 35,000 when selling

35000 - 30000 is 5,000 capital gain

4 0

2 years ago

Read 2 more answers

Match the integrals with the type of coordinates which make them the easiest to do.

WARRIOR [948]

Answer:

1. C. cylindrical coordinates

2 A. spherical coordinates

3. A. spherical coordinates

4. D. Cartesian coordinates

5 B. polar coordinates

Step-by-step explanation:

USE THE BOUNDARY INTERVALS TO IDENTIFY

1. ∭E dV where E is:

x^2 + y^2 + z^2<= 4, x>= 0, y>= 0, z>= 0 -- This is A CYLINDRICAL COORDINATES SINCE x>= 0, y>= 0, z>= 0

2. ∭E z^2 dV where E is:

-2 <= z <= 2,1 <= x^ 2 + y^2 <= 2 This is A SPHERICAL COORDINATES

3. ∭E z dV where E is:

1 <= x <= 2, 3<= y <= 4,5 <= z <= 6 -- This is A SPHERICAL COORDINATES

4. ∫10∫y^20 1/x dx ---- This is A CARTESIAN COORDINATES

5. ∬D 1/x^2 + y^2 dA where D is: x^2 + y^2 <=4 This is A POLAR COORDINATES

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2 years ago