Answer:
3x+y=8 and 3x+y=9
Step-by-step explanation:
Assume these two equations:
a1x+b1y+c1=0
a2x+b2y+c2=0
If (a1/a2) = (b1/b2) ≠ (c1/c2) than those two would have no solution.
In these case, take a look at the last option:
Re-write 'em as a standard form:
So (a1/a2) = (b1/b2) ≠ (c1/c2) is true here:
And they do not have any collision point
Answer:
a. converges to s> 1.
b. converges to s> 5.
c. converges to s> - 3.
d. converges to s> 0.
e. converges even s> 0.
f. converges to s> 0.
g. converges to s> 0.
h. converges to s> 0.
Step-by-step explanation:
a. converges to s> 1.
b. converges to s> 5.
c. converges to s> - 3.
d. converges to s> 0.
e. converges even s> 0.
f. converges to s> 0.
g. converges to s> 0.
h. converges to s> 0.
If this is an equilateral triangle, we need half of it to find the height which is a leg of a right triangle with a hypotenuse of 15. That means that the base of this half triangle is 7.5. Use Pythagorean's Theorem to fine the height.
. x = 12.99 or 13
There is some ambiguity here which could be removed by using parentheses. I'm going to assume that you actually meant:
x-3
h(x) = ---------------
(x^3-36x)
To determine the domain of this function, factor the denominator:
x^3 - 36x = x(x^2 - 36) = x(x-6)(x+6)
The given function h(x) is undefined when the denominator = 0, which happens at {-6, 0, 6}.
Thus, the domain is "the set of all real numbers not equal to -6, 0 or 6."
Symbolically, the domain is (-infinity, -6) ∪ (-6, 0) ∪ (0, 6) ∪ (6, +infinity).