Which expression will help find the volume of the figure?

Mathematics

1 answer:

Alex Ar [27]2 years ago

7 0

Answer:

9*4*1*2

Step-by-step explanation:

9×4×1×2

Its because you need all the values to find the volume

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F(x)=-2x^2+4x+5<br> Find the critical numbers

frez [133]

Answer:

To find critical points, take the first derivative and set it equal to zero:

f(x) = -2x^2 + 4x + 5

f'(x) = -4x + 4

-4x+4 = 0

-4x = -4

x = 1

Critical point at x = 1

Alternatively, if you mean zeros, or where the x intersects, you can use the quadratic equation.

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If sin A = 3/8, find the value of cosec A - sec A.

alexira [117]

Answer:

$\csc A - \sec A = \dfrac 83 + \dfrac{8}{\sqrt{55}}\\\\\csc A - \sec A = \dfrac 83 - \dfrac{8}{\sqrt{55}}$

Step by step explanation:

$\text{Given that,}\\\\~~~~~~\sin A = \dfrac 38 \\\\\implies \sin^2 A = \dfrac 9{64}\\\\\implies 1 - \cos^2 A = \dfrac{9}{64}\\\\\implies \cos ^2 A = 1 - \dfrac 9{64}\\\\\implies \cos^2 A = \dfrac{55}{64}\\\\\implies \cos A =\pm\sqrt{\dfrac{55}{64}}\\ \\\implies \cos A = \pm\dfrac{\sqrt{55}}8\\\\$

$\implies \dfrac 1{\cos A} = \pm\dfrac{8}{\sqrt{55}}$

$\text{Now,}\\\\\csc A - \sec A\\\\=\dfrac{1}{\sin A}- \dfrac{1}{\cos A}\\\\=\dfrac 83 -\left(\pm \dfrac 8{\sqrt {55}} \right)\\ \\\text{Hence,}\\\\\csc A - \sec A = \dfrac 83 + \dfrac{8}{\sqrt{55}}\\\\\csc A - \sec A = \dfrac 83 - \dfrac{8}{\sqrt{55}}$