so we have a 60-30-90 triangle (top one)
so since we know 6 is x (the side on the right angle and 60 degrees)
b is 2x or 2(6) = 12
a is x√3 = 6√3
for C I need to use a 45 45 90 triangle
Since b is 12 and its x√2 to find x we should write it as
x√2 = 12
√2 √2 divide by √2
x = 12/√2 but we must rationalize the denominator
12/√2 times √2/√2 = 12√2/2 and that's c
Answer:
119.67
Step-by-step explanation:
a^2 + b^2 =c^2
Step-by-step explanation:
We have given,
A rational function : f(x) =
W need to find :
Point of discontinuity : - At x = 4, f(x) tends to reach infinity, So we get discontinuity point at x =4.
For no values of x, we get indetermined form (i.e ), Hence there is no holes
Vertical Asymptotes:
Plug y=f(x) = ∞ in f(x) to get vertical asymptote {We can us writing ∞ = }
i.e ∞ =
or
or x-4 =0
or x=4, Hence at x = 4, f(x) has a vertical asymptote
X -intercept :
Plug f(x)=0 , to get x intercept.
i.e 0 =
or x - 2 =0
or x = 2
Hence at x=2, f(x) has an x intercept
Horizontal asymptote:
Plug x = ∞ in f(x) to get horizontal asymptote.
i.e f(x) = =
or f(x) =
or f(x) = 1 = y
hence at y =f(x) = 1, we get horizontal asymptote
Answer:
1.01789228E-5
Step-by-step explanation:
hope this helped :)
1. Angles ADC and CDB are supplementary, thus
m∠ADC+m∠CDB=180°.
Since m∠ADC=115°, you have that m∠CDB=180°-115°=65°.
2. Triangle BCD is isosceles triangle, because it has two congruent sides CB and CD. The base of this triangle is segment BD. Angles that are adjacent to the base of isosceles triangle are congruent, then
m∠CDB=m∠CBD=65°.
The sum of the measures of interior angles of triangle is 180°, therefore,
m∠CDB+m∠CBD+m∠BCD=180° and
m∠BCD=180°-65°-65°=50°.
3. Triangle ABC is isosceles, with base BC. Then
m∠ABC=m∠ACB.
From the previous you have that m∠ABC=65° (angle ABC is exactly angle CBD). So
m∠ACB=65°.
4. Angles BCD and DCA together form angle ACB. This gives you
m∠ACB=m∠ACD+m∠BCD,
m∠ACD=65°-50°=15°.
Answer: 15°.