If the length is 2ft longer than it’s width
Let’s assume width as X and so the length will be X+2
Perimeter=40ft
Putting the values into a equation, we get,
X+2+X=40
=2X+2=40
=2X=38
=X=19
Therefore
Length =X+2=19+2
=21ft
Width=X=19ft
Area of rectangle =lxb
= 21x19
3992ft
HOPE IT WAS HELPFUL :)
Make hours to seconds to match meters
19.6*3600=70560 seconds
And is dropped from a height of 15.4 meters then the velocity will be
15.4m/70560s = 0.0002182539m/s
The answer should be 32 2/3. Sorry I'm late, but hope this helps.
The answer is positive 1/5. Here is a tip, when reading a graph read from left to right. If it is going up to the right it is positive. If it goes down going to the right it is negative. Also think rise/run. Count how many times it goes up(or down) then count how long the line goes.
Answer:
(the relation you wrote is not correct, there may be something missing, so I will simplify the initial expression)
Here we have the equation:
We can rewrite this as:
Now we can add and subtract cos^2(x)*sin^2(x) to get:
We can complete squares to get:
and we know that:
cos^2(x) + sin^2(x) = 1
then:
This is the closest expression to what you wrote.
We also know that:
sin(x)*cos(x) = (1/2)*sin(2*x)
If we replace that, we get:
Then the simplification is:
