Let EB and CF be two heights. Then quadrilateral EBCF is rectangle, so BC=EF=5 m. It is given that bases are BC=5 m and AD=11 m. Triangles ABE and DCF are congruent, thus,
Consider right triangle ABE, by the Pythagorean theorem
Answer:
P = 2(L) +2(W)
P = 2(4x+3) + 2(2x)
answer
B. 2(4x+3) + 2(2x)
Answer:
£16.50
Step-by-step explanation:
0, 1/8, 1/4, 1/2, 1/2, 3/4, 1, 4/3, 3, 3, 7/2, 9, 32/3, 15, hope this helps :)
Answer:
47.292
Step-by-step explanation: