The sides could be 10.2 inches or 15.7 inches.
See the attached picture for the equations:
The answer is -14 degrees centigrade
Answer:
The magnitude of the electric force between these two objects
will be: 181.274 N.
i.e. F N
Step-by-step explanation:
As
Two object accumulated a charge of 4.5 μC and another a charge of 2.8 μC.
so
q₁ = 4.5 μC = 4.5 × 10⁻⁶ C
q₂ = 2.8 μC = 2.8 × 10⁻⁶ C
separated distance = d = 2.5 cm
Calculating the magnitude of the force between two charged objects using the formula:
∵
∵
∵
∵
F N
Therefore, the magnitude of the electric force between these two objects will be: 181.274 N.
i.e. F N
D 288 1/3 = 96/288 3/4 = 216/288 5/32 = 45/288 8/9 = 256/288
1/3 times 96 3/4 times 72 5/32 times 9 8/9 times 32
Hope This Helped! :3
Answer:
9 miles
Step-by-step explanation:
A 6+3 is nine