Answer:
15.98 L
Explanation:
First, you need to find T1, T2, V1 and V2.
T1 = 25 C = 298.15 K (25C + 273.15K)
T2 = 100 C = 373.15 K (100C + 273.15K)
V1 = 20. L
V2 = ? (we are trying to find)
Next, rearrange to fit the formula
V2 = V1 x T1 / T2
Next, fill in with our numbers
V2 = 20. L x 298.15 K / 373.15 K
Do the math and you should get...
15.98 L
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Answer:
hexane C6H14
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Explanation:
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Answer:
C. H2O is the base and H3O+ is the conjugate acid
Explanation:
According to Bronsted-Lowry acid-base theory, an acid is a substance that loses an hydrogen ion or proton (H+) while a base is a substance that gains an hydrogen ion (H+) or proton. Furthermore, this theory states that, the molecule formed when an acid donates its proton is called the CONJUGATE BASE, while the molecule formed when the base accepts proton is called CONJUGATE ACID.
In this question, the following equation is given:
NH4+(aq) + H2O(aq) ⇌NH3(aq) + H3O+ (aq)
Water (H2O) is the base in this equation because according to Bronsted-Lowry acid-base theory, it accepts an hydrogen ion (H+) while hydroxonium ion (H3O+) is the conjugate acid.
Answer:
- <u><em>You should expect that the ionic bond in LiBr is stronger than the bond in KBr.</em></u>
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Explanation:
The<em> ionic bonds</em> are formed by the electrostatic attraction between the ions, cations and anions.
In KBr the cation is K⁺ and the anion is Br⁻.
In LiBr the cation is Li⁺ and the anion is Br⁻.
You must expect that the bond strength depends mainly on the charges present on each ion and the distance between them.
Nevertheless, the effect of the distance between the radius dominate the trendency of the bond strength, which makes that the ionic strength trend be related to the ionic radius trend.
Lithium is a smaller ion than Potassium (both are in the same group and Lithium is above Potassium).
Thus, you should expect that the Li ion is closer to the Br ion than what the K ion is to the Br ion and expect that the bond between a Li ion and the Br ion be stronger than the bond between the K ion and the Br ion.