keeping in mind that perpendicular lines have negative reciprocal slopes, hmmm what's the slope of the equation above anyway?
![\bf y = \cfrac{2}{3}x\implies y = \stackrel{\stackrel{m}{\downarrow }}{\cfrac{2}{3}}x+0\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20y%20%3D%20%5Ccfrac%7B2%7D%7B3%7Dx%5Cimplies%20y%20%3D%20%5Cstackrel%7B%5Cstackrel%7Bm%7D%7B%5Cdownarrow%20%7D%7D%7B%5Ccfrac%7B2%7D%7B3%7D%7Dx%2B0%5Cqquad%20%5Cimpliedby%20%5Cbegin%7Barray%7D%7B%7Cc%7Cll%7D%20%5Ccline%7B1-1%7D%20slope-intercept~form%5C%5C%20%5Ccline%7B1-1%7D%20%5C%5C%20y%3D%5Cunderset%7By-intercept%7D%7B%5Cstackrel%7Bslope%5Cqquad%20%7D%7B%5Cstackrel%7B%5Cdownarrow%20%7D%7Bm%7Dx%2B%5Cunderset%7B%5Cuparrow%20%7D%7Bb%7D%7D%7D%20%5C%5C%5C%5C%20%5Ccline%7B1-1%7D%20%5Cend%7Barray%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
so we're really looking for the equation of a line whose slope is -3/2 and runs through (0,0).
3/1200 = 1/400 = 25/10000 = 0.0025
To find the y intercept you must substitute 0 into x.
F(x) = (-3x0) - (6x0) - 5
F(x) = -5
To find the axis of symmetry and vertex we use the formula -b/2a to find the x coordinate
x = 6/(-3x2)
x = 6/-6
x = -1
Now we need to find the y coordinate so we sub -1 into x.
F(x) = (-3x-1) - (6x-1) - 5
F(x) = 3 + 6 - 5
F(x) = 4
The axis of symmetry and vertex are (-1,4) and the y coordinate is -5. Hope this helps.
Answer:
<h2>19.25km</h2>
Step-by-step explanation:
Step one:
given data
we are told that the distance that Rahima covers on a daily is 2.75km long
we also know that a week has 7 days that is Mon-Sunday
Required
the total distance for a week
Step two:
Hence the total distance covered for 7 days is
=2.75*7
=19.25km
<em>Simply multiply the distance covered in a day by 7 to get the distance covered in a week </em>
