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2 years ago

Linzy is having a bake sale. She has 48 chocolate chip cookies and 64 vanilla wafer

Mathematics

1 answer:

Yuliya22 [10]2 years ago

4 0

Answer:

1 bag of 64

2 bags of 32

4 bags of 16

Or 8 bags of 8

Step-by-step explanation:

that's the answer I think for however your answer is there were no answers to pick from....

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Write the complex number in the form a + bí. V6 (cos 315º + i sin 315º)

tatyana61 [14]

Answer:

dude i tried so hard i keep getting da same answer its timing me to do it so ima put da answer in comments

Step-by-step explanation:

8 0

2 years ago

Solve for x. You must write you answer in fully simplified form. -11 = -8x

VLD [36.1K]

inproper fraction form:

$x=\frac{11}{8}$

Decimal form:

$x=1.375$

Mixed number form:

$x=1\frac{3}{8}$

Hope this helps :)

4 0

2 years ago

Read 2 more answers

1; 4; 16; 64; ... what is the general term

Alborosie

Given:

The sequence is

1, 4, 16, 64

To find:

The general term of the given sequence.

Solution:

We have, the sequence

1, 4, 16, 64

Here, the ratio between two consecutive terms is same. So, it is a geometric sequence.

First term is:

$a=1$

Common ratio is:

$r=\dfrac{a_2}{a_1}$

$r=\dfrac{4}{1}$

$r=4$

The nth term of a geometric sequence is

$a_n=ar^{n-1}$ ...(i)

Where, a is the first term and r is the common ratio.

Putting a=1 and r=4 in (i), we get

$a_n=(1)(4)^{n-1}$

$a_n=4^{n-1}$

Therefore, the general term of the given sequence is $a_n=4^{n-1}$ .

8 0

2 years ago

(1/?) Please tell me if these are corect or wrong, If it's wrong, tell me what number I should change

Fofino [41]

Answer:

Yes they are correct

Step-by-step explanation:

8 0

2 years ago

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16. How many different words can be formed with the letters of the word 'RAJARAM'? In how many of

Mandarinka [93]

Answer:

The word "ARRANGE" can be arranged in

2!×2!

5040

=1260 ways.

For the two R's do occur together, let us make a group of R's taking from "ARRANGE" and permute them.

Then the number of ways =

=360.

The number ways to arrange "ARRANGE", where two "R's" will not occur together is =1260−360=900.

Also in the same way, the number of ways where two "A's" are together is 360.

The number of ways where two "A's" and two "R's" are together is 5!=120.

The number of ways where neither two "A's" nor two "R's" are together is =1260−(360+360)+120=660.

Step-by-step explanation:

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7 0

2 years ago

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