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2 years ago

12

N3O4 empirical or molecular

1 answer:

Gnesinka [82]2 years ago

4 0

Answer:

I think its Molecular

Explanation:

You might be interested in

What mass of copper sulphate dissolves in 100g of water at 70 °C

ValentinkaMS [17]

The answer mass of copper sulphate is

46g

6 0

2 years ago

If a 95.27 mL sample of acetic acid (HC2H3O2) is titrated to the equivalence point with 79.06 mL of 0.113 M KOH, what is the pH

KATRIN_1 [288]

Answer:

8.73

Explanation:

The concentration of acetic acid can be determined as follows:

$M_1V_1 = M_2V_2\\(KOH) = (CH_3COOH)$

$M_{KOH}=0.113 M\\V_{KOH}=79.06 mL$

$V_{CH_3COOH}=95.27 \\\\M_{CH_3COOH)=?????$

$M_{CH3COOH} = \frac{M_{KOH}*V_{KOH}}{V_{CH_3COOH}}$

$M_{CH3COOH} = \frac{0.113*79.06}{95.27}$

$M_{CH3COOH} = 0.094 M$

Moles of $CH_3COOH$ = $95.27* 10^{-3}* 0.094$

=0.0090 moles

Moles of $KOH = 79.06*10^{-3}*0.113$

= 0.0090 moles

The equation for the reaction can be expressed as :

$CH_3COOH$ $+$ $KOH$ -----> $CH_3COO^{-}K^+$ $+$ $H_2O$

Concentration of $CH_3COO^{-$ ion = $\frac{0.0090}{Total volume (L)}$

= $\frac{0.0090}{(95.27+79.06)} *1000$

= 0.052 M

Hydrolysis of $CH_3COO^{-$ ion:

$CH_3COO^{-$ $+$ $H_2O$ -----> $CH_3COOH$ $+$ $OH^-$

$K = \frac{K_w}{K_a} = \frac{x*x}{0.052-x}$

⇒ $\frac{10^{-14}}{1.82*10^{-5}}= \frac{x*x}{0.052-x}$

= $0.5494*10^{-9}= \frac{x*x}{0.052-x}$

As K is so less, then x appears to be a very infinitesimal small number

0.052-x ≅ x

$0.5494*10^{-9}= \frac{x^2}{0.052}$

$x^2 = 0.5494*10^{-9}*0.052$

$x^2 = 0.286*10^{-10$

$x = \sqrt{0.286*10^{-10$

$x =0.535*10^{-5}M$

$[OH] = x =0.535*10^{-5}$

$pOH = -log[OH^-]$

$pOH = -log[0.535*10^{-5}]$

$pOH = 5.27$

pH = 14 - pOH

pH = 14 - 5.27

pH = 8.73

Hence, the pH of the titration mixture = 8.73

8 0

2 years ago

Use the following chemical equation to answer the question:

garik1379 [7]

2 atome nitrogen , 1 is correct

5 0

2 years ago

An object has a mass of 20g and occupies a volume of 40 ml. Calculate the Density of the object.

Vsevolod [243]

Answer:

<h3>The answer is 0.5 g/mL</h3>

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question we have

$density = \frac{20}{40} \\$

We have the final answer as

<h3>0.5 g/mL</h3>

Hope this helps you

3 0

2 years ago

5. A 25 ml graduated cylinder has a volume of water of 10 ml, when a glass marble is place in the

IceJOKER [234]

Answer:

The volume of the marble is 10 mL.

Explanation:

From the question given above, the following data were obtained:

Volume of water = 10 mL

Rise in water = 10 mL

Volume of marble =.?

From the question given above, the water level rise by 10 mL when a glass marble was placed into the water.

This is equally the volume of the marble as the marble will displace it's volume when placed in the water according to Archimedes' principle.

Therefore,

Rise in water = 10 mL = volume of marble.

4 0

2 years ago