The question here is solved using basic chemistry. CaCl2(aq) is an ionic compound which will have the releasing of 2 Cl⁻ ions ions in water for every molecule of CaCl2 that dissolves.
CaCl2(s) --> Ca+(aq) + 2 Cl⁻(aq)
[Cl⁻] = 0.65 mol CaCl2/1L × 2 mol Cl⁻ / 1 mol CaCl2 = 1.3 M
The answer to this question is [Cl⁻] = 1.3 M
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You need to use Stoichiometry
Answer:
2 moles of MgCl2.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is given below:
Mg + 2HCl —> MgCl2 + H2
Now, we can determine the number of mole MgCl2 produced from 4 moles of HCl as follow:
From the balanced equation above,
2 moles of HCl reacted to produce 1 mole of MgCl2.
Therefore, 4 moles of HCl will react to produce = (4 x 1)/2 = 2 moles of MgCl2.
Therefore, 2 moles of MgCl2 were produced from the reaction of 4 moles of HCl.
Answer:
The atomic radius of calcium is approximately 175
Explanation:
Given that the atomic radius of magnesium = 150 pm
The atomic radius of strontium = 200 pm
Therefore, given that calcium comes in between magnesium and strontium in group 2 of the periodic table, the atomic radius should be half way between the length of the atomic radius of magnesium and strontium, given that the atomic radius is not a fixed quantity
Therefore;
The atomic radius of calcium is approximately given as follows;
The approximate atomic radius (200 + 150)/2 = 175 pm.
