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Alenkasestr [34]

2 years ago

13

A group of 20 students are going to watch a basketball game. It cost $10 for 4 students to watch a game. How much will the group

pay?

1 answer:

ivolga24 [154]2 years ago

6 0

They will pay 15 dollars

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A(2,4) and B(6,8) . <br>find the midpoint of M

inysia [295]

8-4/6-2 = 2/4 = 1/2

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2 years ago

Read 2 more answers

Complete the square 2m2−3m=−50

rusak2 [61]

Answer:

Completing the square answer

$\left(m - \frac{3}{4}\right)^2 = - \frac{391}{16}$

Solution set

$m = \frac{3}{4} + \frac{\sqrt[]{391}i}{4} = 0.75 + 4.94343 \, i$

$m = \frac{3}{4} - \frac{\sqrt[]{391}i}{4}$ = $0.75 - 4.94343 \, i$

Step-by-step explanation:

Assuming the question is correctly interpreted as 2m2 = 2m², here is how to proceed

We have $2m^2 - 3m =-50$

Divide by 2 on both sides

$m^2 - \frac{3}{2}m = - 25$

Take half of the coefficient of $x$ and square it

$\left[ - \frac{3}{2} \cdot \frac{1}{2} \right]^2 = \frac{9}{16}$

Add the result to both sides

$m^2 - \frac{3}{2}m + \frac{9}{16} = - 25 + \frac{9}{16}$

$m^2 - \frac{3}{2}m + \frac{9}{16}$ can be re-written as a perfect square

$\left(m - \frac{3}{4}\right)^2$

The RHS becomes

$- 25 + \frac{9}{16} = \frac{(-25)(16) + 9}{9} = \frac{-391}{16}$

Therefore,

$\left(m - \frac{3}{4}\right)^2 = - \frac{391}{16}$

Take the square root of both side

$m - \frac{3}{4} = \pm \sqrt[]{ - \frac{391}{16}}$

Simplify

$m - \frac{3}{4} = \pm \frac{\sqrt[]{391}i}{4}$

Adding $\frac{3}{4}$ both sides

$m = \frac{3}{4} + \frac{\sqrt[]{391}i}{4}$

This gives the two solutions

$m= \frac{3}{4} + \frac{\sqrt[]{391}i}{4}$ and

$m = \frac{3}{4} - \frac{\sqrt[]{391}i}{4}$

which becomes

$m = 0.75 + 4.94343 \, i$ and

$m = 0.75 - 4.94343 \, i$

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Approximately 6.6 ft !

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Dan rolled a number cube 20 times. the cube landed on fhe number 3 six times.

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Solve for x 3(x+2)+4=5x+7

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Distribute: 3x+6+4=5x+7
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