Answer:
378mL
Explanation:
The following data were obtained from the question:
Pressure (P) = 99.19 kPa
Temperature (T) = 28°C
Number of mole (n) = 0.015 mole
Volume (V) =...?
Next, we shall convert the pressure and temperature to appropriate units. This is illustrated below:
For Pressure:
101.325 KPa = 1 atm
Therefore, 99.19 kPa = 99.19/101.325 = 0.98 atm
For Temperature:
T(K) = T(°C) + 273
T(°C) = 28°C
T(K) = 28°C + 273 = 301K.
Next we shall determine the volume of N2. The volume of N2 can be obtained by using the ideal gas equation as shown below:
PV = nRT
Pressure (P) = 0.98 atm
Temperature (T) = 301K
Number of mole (n) = 0.015 mole
Gas constant (R) = 0.0821atm.L/Kmol.
Volume (V) =...?
0.98 x V = 0.015 x 0.0821 x 301
Divide both side by 0.98
V = (0.015 x 0.0821 x 301) /0.98
V = 0.378 L
Finally, we shall convert 0.378 L to millilitres (mL). This is illustrated below:
1L = 1000mL
Therefore, 0.378L = 0.378 x 1000 = 378mL
Therefore, the volume of N2 collected is 378mL
First, we need to know what's the gravity value in the moon. it is 1.622 m/ s2
to find the force, let's recall this formula----> Force= mass x gravity
force= 83 kg x 1.622= 134.6
A is the closest choice.
Answer:
A carbohydrate is a compound composed of molecules of carbon (C), hydrogen (H), and oxygen (O) such that its general chemical formula is .
Biochemical functions of carbohydrates: Carbohydrates provide Stored Energy, Carbohydrates help to preserve Muscle and promote digestive health and Carbohydrates build macromolecules
Explanation:
A carbohydrate is a compound composed of molecules of carbon (C), hydrogen (H), and oxygen (O) such that its general chemical formula is .
Biochemical functions of carbohydrates:
1. Carbohydrates provide Stored Energy.
2. Carbohydrates help to preserve Muscle and promote digestive health.
3. Carbohydrates build macromolecules
Answer:
[O2(g)][SO2(g)]^2/[SO3(g)]^2
Explanation:
The given cell reaction is as follows.
Hence, reactions taking place at the cathode and anode are as follows.
At anode ; Oxidation-half reaction : ...... (1)
At cathode; Reduction-half reaction : ....... (2)
Hence, balance the half reactions by multiplying equation (1) by 2 and equation (2) by 3.
Therefore, net cell reaction is as follows.
Net reaction:
Thus, we can conclude that the overall cell reaction is as follows.