Ask question

Ask question

All categories

1 year ago

10

a square field has a side 150 m long .There is a road 5 m wide all around the park outside it .Find the cost of constructing the

road at 250 rupees per sq metre

1 answer:

alisha [4.7K]1 year ago

6 0

Answer:

Cost to construct the road = 775000 rupees

Step-by-step explanation:

Square field has a side = 150 m

Area of the field = (Side)²

= (150)²

= 22500 m²

Length of the park with road around the field = 150 + 2×(width of the road)

= 150 + (2×5)

= 160 m

Similarly, width of the park with road around the field = 160 m

Area of the park with road = (Side)²

= (160)²

= 25600 m²

Area of road = Area of the park with road - Area of the park

= 25600 - 22500

= 3100 m²

Since, cost of constructing the road = 250 rupees per square meter

Cost to construct the road with the given area = 250 × 3100

= 775000 rupees

You might be interested in

Which pair of funtions is not a pair of inverse functions? please help!!

antiseptic1488 [7]

Answer:

$f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Step-by-step explanation:

we know that

To find the inverse of a function, exchange variables x for y and y for x. Then clear the y-variable to get the inverse function.

we will proceed to verify each case to determine the solution of the problem

<u>case A)</u> $f(x)=\frac{x+1}{6} , g(x)=6x-1$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y+1}{6}$

Isolate the variable y

$6x=y+1$

$y=6x-1$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=6x-1$

therefore

f(x) and g(x) are inverse functions

<u>case B)</u> $f(x)=\frac{x-4}{19} , g(x)=19x+4$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y-4}{19}$

Isolate the variable y

$19x=y-4$

$y=19x+4$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=19x+4$

therefore

f(x) and g(x) are inverse functions

<u>case C)</u> $f(x)=x^{5}, g(x)=\sqrt[5]{x}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=y^{5}$

Isolate the variable y

fifth root both members

$y=\sqrt[5]{x}$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=\sqrt[5]{x}$

therefore

f(x) and g(x) are inverse functions

<u>case D)</u> $f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y}{y+20}$

Isolate the variable y

$x(y+20)=y$

$xy+20x=y$

$y-xy=20x$

$y(1-x)=20x$

$y=20x/(1-x)$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=20x/(1-x)$

$\frac{20x}{1-x}\neq \frac{20x}{x-1}$

therefore

f(x) and g(x) is not a pair of inverse functions

7 0

2 years ago

Read 2 more answers

Can someone help me with this math question i really don’t know how to do it!

julia-pushkina [17]

Answer:

1260

Step-by-step explanation:

He asked 180 people and 63 said cookies so I think you have to do 63 out of each 180 people so you would do 3600 ÷ 180 = 20, 20 x 63 =1260

Not sure if this is right, hope this helps

8 0

2 years ago

Andy estimated that he would need 79 feet of lumber for a tree house project. He later found that the actual amount of lumber ne

Radda [10]

Answer:

Step-by-step explanation:

79 divided by 68 is your answer

You can do the math

5 0

2 years ago

The cost, C, in millions of dollars of producing T million tons of steel is modeled by the equation C = 220T + 1890.

kobusy [5.1K]

C = 220T + 1890.

Solve the equation for T.

220T = C - 1890

T = C/220 - 8.6

The steel produced is expected to be sold at a price of $310 per ton.

310 $/ton is a rate or slope. Write a linear equation where x is tons of steel produced and y is selling price of the steel.

y = 310x

Write and solve an equation to find the amount of steel produced if the selling price is equal to the cost of production.

* Here, note that the cost of production and tons of steel in the first equation is in the millions. The equation we just wrote for the selling price was in x tons of steel. This only matters in regards to the units you specify because; million/million = 1

The unit multiplier of all variables must be specified as same. Either everything is in millions or not.

Here, I'll leave everything in millions, change x (tons of steel) to T (mill tons steel) and "y" to "S" in million dollars selling price.

S = 310T

Set equal to Cost equation.

220T + 1980 = 310T

Solve for T, million tons of steel produced.

1980 = 310T - 220T

1980 = 90T

T = 1980/90

T = 22 million tons steel produced

7 0

2 years ago

What is the sum of three consecutive odd integers is 75?

tankabanditka [31]

Odd integers are 2 apart
they are n, n+2, n+4

the sum is 75

n+n+2+n+4=75
3n+6=75
minus 6 both sides
3n=69
divide both sides by 3
n=23
n+2=25
n+4=27

the integers are 23,25,27

7 0

2 years ago