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2 years ago

I pleased anyone to help me please

Mathematics

2 answers:

Gennadij [26K]2 years ago

3 0

Answer:

The first one (90, 90) is supplimentary, the next two (54, 36. and 45, 45) are complimentary, and the last two are supplimentary.

Step-by-step explanation:

A complimentary angle is two angles that add up to 90, and supplimentary is two angles that add up to 180! :)

Flauer [41]2 years ago

3 0

Answer:

1st picture at the top would be a supplementary angle because a supplementary angles always add to 180 degrees.

the 54 and 36 one is a complementary angle

the 45 and 45 would be complementary angle

the last two on the bottom would both be supplementary angles.

High hopes-

Barry

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2 years ago

Jonathan's age is 1/3 Belinda's age now in 12 years Belinda will be m years old write an algebraic expression to represent Brend

vodomira [7]

Answer:

Kindly check explanation

5 years from now, Johnathan will be (5 + 4) = 9 years

Step-by-step explanation:

Let Belinda's age = x

Jonathan's age =1/3 x

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Belinda's age now = x

Jonathan's age 5 years from now, if m = 36

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2 years ago

7/8y + 1/2 = 1 1/5 Solve for y.

abruzzese [7]

Answer:

y = 4/5

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Step-by-step explanation:

Step 1: Define

Identify

7/8y + 1/2 = 1 1/5

Step 2: Solve for y

Convert to improper fraction: 7/8y + 1/2 = 6/5
[Subtraction Property of Equality] Subtract 1/2 on both sides: 7/8y = 7/10
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2 years ago

Select the correct location in the expression.

kogti [31]

Answer:

Correct term:60

Step-by-step explanation:

We are given that

$\frac{4x^4-6x^3+6x+3}{x-3}$

The quotient of this expression is given by

$4x^3+6x^2+18x+78+\frac{183}{x-3}$

We have to find the term in this expression which contains an error.

$\frac{4x^4-6x^3+6x+3}{x-3}$

The quotient of this expression is given by

$=4x^3+6x^2+18x+60$

$Dividend=Divisor\times quotient+ remainder$

Using the formula

$4x^4-6x^3+6x+3=(x-3)(4x^3+6x^2+18x+60)+\frac{183}{x-3}$

We can see that in the given expression there is 60 in place of 78.

The error in the expression of quotient is 78.

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2 years ago

I pleased anyone to help me please​

I pleased anyone to help me please