Where’s the triangle, isn’t there supposed to be a picture with the question
Answer:
Step-by-step explanation:
Given
Required
Determine the inverse function
Start by replacing f(x) with y
Swap the positions of y and x
Make y the subject: <em>Add 4 to both sides</em>
Make y the subject: <em>Divide through by 2</em>
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Replace y with f-1(x)
Answer:
Step-by-step explanation:
I'm assuming you meant to type in
because you can only have removable discontinuities where there is a rational (fraction) function. Begin by factoring both the numerator and denominator to
and cancelling out like terms would have us eliminating the (x + 3). That is where there is a removable discontinuity. It leaves a hole. The other discontinuity, (x + 1) doesn't cancel out so it is a non-removable discontuinity, which is a vertical asymptote.
The removable discontinuity is at -3. There is no y value at x = -3 (remember there's only a hole here), because -3 causes the denominator to go to 0 and we all know that having a 0 in the denominator of a fraction is a big no-no!!!
a) <u>n² + 6 </u>
~Here n is the number of term. So, put n = 1,2,3,4.... to get the term.
- If n = 1, first term = 1² + 6 = 7
- n = 2, second term = 10
- n = 3, third temm = 15
- n = 4, fourth term = 22
- n = 10, tenth term = 106
b) <u>3n²</u>
- If n = 1, first term = 3
- n = 2, second term = 12
- n = 3, third term = 27
- n = 4, fourth term = 48
- n = 10, tenth term = 300