Answer:
I am just guessing but I think its A
Explanation:
because moss needs the nutrients to survive
Pathogens can exist in blood and then can be passed the transfusions
Answer:
Option B, not phosphorylated; inhibited
Explanation:
Glucose 6 acts as a catobolite repressant . A catobolite repressant which is usually a carbon compound inhibits the operon transcription. In the presence of glucose -6, unphosphorylated enzyme IIAGlc inhibits the transportation system and hence prevents the utilization of lactose. Glucose‐6‐phosphate and other non‐PTS carbon causes inducer exclusion thereby leading to dephosphorylation of enzyme IIAGl without getting transported.
Hence, option B is correct
Answer:
its either a or b i don't know exactly cuz I didn't learn this but I tried looking it up and it didn't work
Getting the probability for each event can easily be done using Punnett Square (say, Hh x Hh for the couple since they are both carriers of the disease). Doing so will result to: 0.25 probability of an offspring not having the disease and is not a carrier of the gene, 0.50 probability of an offspring not having the disease and is a carrier of the gene, and a 0.25 probability of an offspring having the disease. The probability of these events apply to each offspring, and will not depend on how many children they want to have. This means each offspring has a 0.25-0.50-0.25 chance of not being a carrier, being a carrier, and having the disease, respectively.
