Answer:
First, find tan A and tan B.
cosA=35 --> sin2A=1−925=1625 --> cosA=±45
cosA=45 because A is in Quadrant I
tanA=sinAcosA=(45)(53)=43.
sinB=513 --> cos2B=1−25169=144169 --> sinB=±1213.
sinB=1213 because B is in Quadrant I
tanB=sinBcosB=(513)(1312)=512
Apply the trig identity:
tan(A−B)=tanA−tanB1−tanA.tanB
tanA−tanB=43−512=1112
(1−tanA.tanB)=1−2036=1636=49
tan(A−B)=(1112)(94)=3316
kamina op bolte
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Answer:
A parallelogram with one right angle is a rectangle. A quadrilateral whose diagonals are equal and bisect each other is a rectangle.
Step-by-step explanation:
2(x+2)=3(x-3)
2x+4=3x-9
2x=3x-13
-x=-13
x=13
The number is 13
Answer:
The description according to the framework in question is illustrated in the portion below.
Step-by-step explanation:
- These same 2 histograms are quite dissimilar or separate, for City A, each information collected has always been largely focused at 400, although for City B, these same results are interpreted at 400.
- The price increases including its households throughout City B have quite a higher SD than those of the exchange rates throughout City A, also because documentation from City A generate a lot of price levels close to the middle of the bar chart, as well as the wages throughout City B, require a high amount of rates farther from the midpoint of the
Answer:
option B (28/52)
Step-by-step explanation:
from probability
P(A∪B)=P(A)+P(B)-P(A∩B)
where
P(A∪B) = probability that event A or B happen
P(A∩B) = probability that event A and B happen simultaneously
P(A) = probability that event A happen
P(B) = probability that event B happen
the probability that the card is special or red
P( special or red)= P(special) + P(red) - P( special and red)
since
P(special)= 4/52
P(red) = 26/52
P( special and red) = 2/52
therefore
P( special or red)= 4/52 + 26/52 - 2/52 = 28/52
P( special or red)= 28/52
(option B)