Ask question

Ask question

All categories

2 years ago

7

According to a certain central bank from 2000 to 2016 the average price of a new home in a certain region increased by %87 to

$ 572 thousand. What was the average price of a new home in 2000?

1 answer:

ch4aika [34]2 years ago

6 0

X*1.87= 572
X=572/1.87
X=$306

You might be interested in

WILL GIVE BRAINLIEST!! Need answer fast!!! <br> 16x > - 2

Alexus [3.1K]

Answer:

x > -1/8 hope helps

4 0

2 years ago

Read 2 more answers

Find x 4.0 58 degrees

timama [110]

Answer: 4.7

<u>Step-by-step explanation:</u>

Use Soh Cah Toa

$sin \theta=\dfrac{opposite}{adjacent}\\\\\\sin(58^o)=\dfrac{4.0}{x}\\\\\\x=\dfrac{4.0}{sin(58^o)}\\\\\\x=4.7$

4 0

2 years ago

Read 2 more answers

Help me plzzzzzzz! I need this today!

makkiz [27]

Answer:

it looks like y int is about 2550

Step-by-step explanation:

3 0

1 year ago

{(8.3), (-2.9), 7,5), (0.6)}<br> Is this a function

hodyreva [135]

Answer:

Yes, it is a function

8 0

2 years ago

Use the surface integral in Stokes' Theorem to calculate the circulation of the field Bold Upper F equals x squared Bold i plus

Tom [10]

Stokes' theorem says the integral of the curl of $\vec F$ over a surface $S$ with boundary $C$ is equal to the integral of $\vec F$ along the boundary. In other words, the flux of the curl of the vector field is equal to the circulation of the field, such that

$\displaystyle\iint_S\nabla\times\vec F\cdot\mathrm d\vec S=\int_C\vec F\cdot\mathrm d\vec r$

We have

$\vec F(x,y,z)=x^2\,\vec\imath+4x\,\vec\jmath+z^2\,\vec k$

$\implies\nabla\times\vec F(x,y,z)=4\,\vec k$

Parameterize the ellipse $S$ by

$\vec s(u,v)=\dfrac{u\cos v}{\sqrt5}\,\vec\imath+\dfrac{u\sqrt5\sin v}4\,\vec\jmath$

with $0\le u\le1$ and $0\le v\le2\pi$ .

Take the normal vector to $S$ to be

$\dfrac{\partial\vec s}{\partial\vec u}\times\dfrac{\partial\vec s}{\partial\vec v}=\dfrac u4\,\vec k$

Then the flux of the curl is

$\displaystyle\iint_S4\,\vec k\cdot\dfrac u4\,\vec k\,\mathrm dA=\int_0^{2\pi}\int_0^1u\,\mathrm du\,\mathrm dv=\boxed{\pi}$

4 0

2 years ago