Solution (1)
for k=0 / for k=1 / for k=-1
x=0 / x=2π / x=-2π
acc / acc / rej
solution (2)
for k=0 / for k=1 / for k=-1
x=0 / x=2π/3 / x=-2π/3
acc / acc / rej
Note that i'm trying values of K which make the answer belong to our interval;
So our solution which i will represent as a set is;
S € {0,2π/3,2π}
<span>1. A = 1/4s squared, square root of 3 equilateral triangle
2. A = bh rectangle
3. A = pi(r) squared circle area
4. A = 1/2 h (b1+ b2) trapezoid
5. C = pi(d) circle circumference
6. A = base x altitude parallelogram
7. A = 1/2(ap) regular polygon
8. A = 1/2(bh) triangle
</span><span>- regular polygon
- trapezoid
- parallelogram
- circle circumference
- equilateral triangle
- circle area</span>
The 7 in 701,280 is in the hundred thousands place.
6x=18 (2x+5) x=6x+15. x-15=6x 5x=15 x=3
Answer:
3x²
Step-by-step explanation:
=
=