Might have to experiment a bit to choose the right answer.
In A, the first term is 456 and the common difference is 10. Each time we have a new term, the next one is the same except that 10 is added.
Suppose n were 1000. Then we'd have 456 + (1000)(10) = 10456
In B, the first term is 5 and the common ratio is 3. From 5 we get 15 by mult. 5 by 3. Similarly, from 135 we get 405 by mult. 135 by 3. This is a geom. series with first term 5 and common ratio 3. a_n = a_0*(3)^(n-1).
So if n were to reach 1000, the 1000th term would be 5*3^999, which is a very large number, certainly more than the 10456 you'd reach in A, above.
Can you now examine C and D in the same manner, and then choose the greatest final value? Safe to continue using n = 1000.
Answer:
An = 32 - (4*(n-1))
Step-by-step explanation:
the starting term for this pattern is 32 (which you will need to include in the "rule")
you also know that the next term is the previous term - 4
so!
we can write this pattern as
An = 32 - (4*(n-1))
An = any number of term in the pattern
- ex). A2 = 28, A3 = 24, etc
n = the nth term
- the 3rd term = 24, the fourth term = 20, etc
Answer:
Quadrilateral
Step-by-step explanation:
The definition of a parallelogram is a quadrilateral that has two sets of parallel sides.
Let
M---------------> money borrowed -------------> <span>$9,850
r--------------> </span>discounted rate--------> <span>9 ¼=9.25-------> 0.0925
t---------------> time--------> </span><span>9 months=9*30=270 days
D-------------> </span><span>amount of the discount
we know that
D=M*r*t/360=(9850)*(0.0925)*(270/360)=683.34
the answer is $683.34</span>
Answer:
14
Step-by-step explanation:
a=1
b=2
d=2
c=10
K+L = 10¹+2² = 10+4 = 14
