Answer:
Yes, but only if it's sunny.
Explanation:
As you know, solar panels generate energy through the sun's rays of light (better known as sunlight). Therefore, as long as the sun is shining high in the sky, the car will generate electricity and be able to function. If this vehicle was only powered by solar panels, it would not function during the night, in cloudy areas, and/or in dark places (such as parking garages or home garages).
Hope this helps!
Answer: the first answer is correct
Explanation:
she goes back to a stable feeling
You don't convert kilograms to newtons. By the time you've heard of these units, you know that 'kilogram' is a unit of mass, 'newton' is a unit of force or weight, and that mass and weight are different things.
Mass and force are <u>related</u> by Newton's second law:
Force = Mass x acceleration .
From this simple formula, you can see that in order to relate a mass to a force, you need to know an acceleration. And if the acceleration changes, then the relationship between the force and the mass also changes. So there's no direct conversion.
ON EARTH ONLY, one kilogram of mass <em>weighs</em> 9.8 newtons. The acceleration that connects them is the acceleration of gravity on Earth. In other places, with different gravitational accelerations, 1 kilogram weighs more or less newtons.
But they don't convert directly. That would be like asking "How do you convert miles to miles-per-hour ?"
Answer:
The one which falls on feet.
Explanation:
Because it exerts higher pressure as
P= F/ A
Larger the area less will be the pressure and less is the area larger will be the pressure.
<h2>
Answer:</h2>
38.14Ω
<h2>
Explanation:</h2>
Let's solve this question using Ohm's law which states that the current (I) flowing through a conductor is directly proportional to the potential difference or voltage (V) across it. Mathematically;
V = I R -------------------(i)
<em>Where</em>;
R is the constant of proportionality called resistance of the conductor and is measured in Ohms (Ω)
<em>From the question;</em>
V = 18.5V
I = 0.485A
<em>Substitute these values into equation (i) as follows;</em>
18.5 = 0.485 x R
<em>Solve for R;</em>
R = 18.5 / 0.485
R = 38.14Ω
Therefore the resistance of the bulb is 38.14Ω