<u>Answer</u>
y = (1/2)x - 1
<u>Explanation</u>
The first step is to get the gradient of the line.
The two points in the line are; (2,0) and (-2, -2).
Gradient = (-2 - 0)/(-2, - 2)
= -2/-4
= 1/2
To get the function we use one of the point (2,0) and a general point (x,y).
1/2 = (y - 0)/(x - 2)
1/2 = y/(x - 2)
(x - 2) = 2y
2y = x - 2
y = (1/2)x - 1
Answer:
A = 1/2 B H area = 1/2 base X height
B = 2 A / H = 2 * 99 / 12 = 16.5 cm
dA / d t = 1/2 * (B dH / dt + H dB / dt)
dB / dt = (2 dA / dt - B dH / dt) / H
dB / dt = (2 * 1.5 cm^2 / min - 16.5 cm * 2 cm / min) / 12 cm
dB / dt = (3 - 33) / 12 cm/min = -2.5 cm/min
Answer:
Can you show me the pattern?
Hi!
For this equation, you can solve it by using the quadratic formula:
x=-b<span>±sqrt/b^2-4ab
-----------------------
2a</span>
<h2>=√(-8-(-6))^+(-4-1)^</h2><h2>=√(-2)^+(-5)^</h2><h2>= -2-5</h2><h2>= -7</h2>