A) Variance = 10.24
B) Standard Deviation = 3.2
One of the measurements of dispersion is the standard deviation, which is exclusively used for quantitative data. It aids in determining if the data's mean is a suitable measurement to reflect the core value.
TIME FREQUENCY(f) MIDPOINT(x) d d² fd fd²
0 - 0.9 43 0.45 -3 9 -129 387
1.0 - 1.9 17 1.45 -2 4 -34 68
2.0 - 2.9 19 2.45 -1 1 -19 19
3.0 - 3.9 18 3.45 0 0 0 0
4.0 - 4.9 14 4.45 1 1 14 14
5.0 -5.9 16 5.45 2 4 32 64
∑f = 127
∑fd = -136
∑fd² = 552
Standard Deviation =
√4.35 - √1.15
Standard Deviation = 3.2
(SD)² = (3.2)² = 10.24
Variance = 10.24
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Answer:
you should take the time and study
Step-by-step explanation:
Convert to improper frist
2 and 7/8=16/8+7/8=23/8
2 and 1/4=8/4+1/4=9/4
(23/8)/(9/4)
make bottom 1
times the whole thing by (4/9)/(4/9)
(92/72)/(36/36)=
92/72=
23/18
You can divide 110 by 1 to see how many 1's go in 110:
110/1 = 110
This means that there are 110 1's in 110.
Hope this helps! :)
-24xy^6 is that simplified