How does the electric field intensity vary with the increase of distance of the point from the centre of a charged conducting sp

Question

2 years ago

8

here? Explain with graph.

1 answer:

Nataly_w [17] · Answer 1 · 2022-04-18T18:11:36+03:00

Answer:

(i) Electric field outside the shell:

For point r>R; draw a spherical gaussian surface of radius r.

Using gauss law, ∮E.ds=q0qend

Since E is perpendicular to gaussian surface, angle betwee E is 0.

Also E being constant, can be taken out of integral.

So, E(4πr2)=q0q

So, E=4πε01r2q