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2 years ago

Find the value of x in the trapezoid below. 124°

Mathematics

2 answers:

sergejj [24]2 years ago

8 0

Answer:

56 degrees

Step-by-step explanation:

just cause

Semmy [17]2 years ago

5 0

Answer:

56 degrees

Step-by-step explanation:

the total degrees in a quadrilateral is 360

and in a trapezoid the top two angles measure the same and the bottom two measure the same

so since one of the top angles is 124 the one beside it is too

add 124 and 124 you get 248

then subtract it from 360 and you get 112

divide 112 by 2 and you get 56 which is the angle of x

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Tamiku [17]

Answer:

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Step-by-step explanation:

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2 years ago

Which number is not the square of a whole number A: 100

abruzzese [7]

10^10 = 100
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29^29 = 841
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5 0

2 years ago

PLS PLS HELP, I DONT WANT TO FAIL!!

Flura [38]

Answer:

2.0 seconds

Step-by-step explanation:

Given quadratic functions:

$\begin{cases}y=-7x^2+26x+3\\y=-6x^2 +23x+5\end{cases}$

To find the time, in seconds, that the balloons collided at the highest point, substitute one equation into the other equation and rearrange to equal zero:

$\begin{aligned}-6x^2+23x+5 & = -7x^2+26x+3\\-6x^2+23x+5+7x^2 & = -7x^2+26x+3+7x^2\\x^2+23x+5 & = 26x+3\\x^2+23x+5-26x & = 26x+3-26x\\x^2-3x+5& = 3\\x^2-3x+5-3& = 3-3\\x^2-3x+2& = 0\end{aligned}$

Factor the quadratic:

$\begin{aligned}x^2-3x+2 & = 0\\x^2-2x-x+2 & = 0\\x(x-2)-1(x-2) & = 0\\(x-1)(x-2) & = 0\\\end{aligned}$

Apply the zero-product property to solve for x:

$\implies (x-1)=0 \implies x=1$

$\implies (x-2)=0 \implies x=2$

Therefore, the balloons collided at 1 second and 2 seconds.

To find at which time the highest point of collision occured, substitute both values of x into one of the functions:

$f(1)=-6(1)^2 +23(1)+5=22$

$f(2)=-6(2)^2 +23(2)+5=27$

Therefore, the time, in seconds, that the balloons collided at the highest point is 2.0 seconds.

Learn more about quadratic systems of equations here:

brainly.com/question/27930827

8 0

10 months ago

Read 2 more answers

The hypotenuse of a right triangle is 50 millimeters long. One leg of the right triangle is 30 millimeters long. What is the len

alexandr1967 [171]

First. we use the Pythagorean theorem:
$a {}^{2} + b {}^{2} = c {}^{2}$
Add the numbers in
${30}^{2} + {b}^{2} = {50}^{2}$
start simplifying
${b}^{2} = 1600$
$b = 40$

So, the leg has a length of 40 mm.

6 0

3 years ago

Triangle DEF has sides with lengths of 6, 11, and 13 units. Determine whether this triangle is a right triangle. Show all work n

mario62 [17]

Answer:

Triangle DEF is not a right triangle ; possible lengths are 20 & 15

Step-by-step explanation:

For right triangle;

the sum of the square of the two adjacent sides must equal the square of the hypotenus.

Therefore, (6^2)+(11^2)≠(13^2).

the possible length are 20 & 15 because

(20^2)+(15^2)=(25^2)

8 0

2 years ago