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2 years ago

Which point lies on the bisector?

Mathematics

2 answers:

guapka [62]2 years ago

8 0

Answer:

Point Y

Step-by-step explanation:

I have attached a picture of me showing which point lies on the bisector since it says to bisects <C of polygon ABCDE.

Hope this helps, thank you :) !!

Liono4ka [1.6K]2 years ago

7 0

Point y is the one on the bisector

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2 years ago

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Which shows the following expression using positive exponents?

Hitman42 [59]

Answer:

1. option B is correct i.e., $\frac{-3a^{7}b^3b^1}{15a^{2}}$

2. option D is correct i.e., $\frac{a^3b^4}{ab^2}$ .

3. option B is correct i.e., $\frac{n^{10}}{16m^{6}}$ .

Step-by-step explanation:

1. Since the given equation is:

$\frac{-3a^{-2}b^3}{15a^{-7}b^{-1}}$

As we know that $a^{-x}=\frac{1}{a^x}$

So, the given equation can be represented as:

$\frac{-3a^{7}b^3b^1}{15a^{2}}$

2. Given equation is:

$\frac{a^3b^{-2}}{ab^{-4}}$

As we know that $a^{-x}=\frac{1}{a^x}$

so the given equation can be represented as:

$\frac{a^3b^4}{ab^2}$ .

3. Given equation is:

$(\frac{4mn}{m^{-2}n^6})^{-2}$

by using the properties $a^{-x}=\frac{1}{a^x}$ ,

and $a^x\times a^y=a^{x+y}$

$(\frac{4mn}{m^{-2}n^6})^{-2}$

= $(\frac{4n^1n^{-6}}{m^{-2}m^{-1}})^{-2}$

= $(\frac{4n^{1+(-6)}}{m^{-2+(-1)}})^{-2}$

= $(\frac{4n^{-5}}{m^{-3}})^{-2}$

= $\frac{4^{-2}n^{-5\times (-2)}}{m^{-3\times (-2)}}$

= $\frac{n^{10}}{16m^{6}}$ .

which is option B.

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2 years ago

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−3x+3y=9 2x−7y=−14

svet-max [94.6K]

(x, y) = (-7/5, 8/5)

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