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2 years ago

Madison used 4 pears and 12 apples to make a fruit salad. What is the ratio of the

Mathematics

1 answer:

kobusy [5.1K]2 years ago

7 0

The answer is 4

So the ratio would be 12/4
Then u simplify into 4/1 ( I divided each number by 4)

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Please help with all of these!!! VERY URGENT!!!

nlexa [21]

1. The coefficient is 5
2. The terms are 2x, 4y, and 8
3. The variables are c, cd, d and d
4. The constants are 2 and 14

5 0

2 years ago

Read 2 more answers

Angela ordered 2 glass paperweights. The volume of each paperweight is 5 cubic inches, and the density of the glass is 1.5 ounce

Katarina [22]

Answer:

$(2\times 5)\times 1.5$

Step-by-step explanation:

Since, according to associative property of multiplication,

a(bc) = (ab)c,

Where a, b and c are any real numbers,

Here, the given expression,

2 × ( 5 × 1.5 ),

By applying the associative property of multiplication,

( 2 × 5 ) × 1.5,

Hence, the appropriate expression in the first box is '(2×5)'

And, the appropriate number in the second box is '1.5'.

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3 years ago

Priya can bike 150 meters in 20 seconds at this rate , how long would it take her to bike in 3,000 meters???????? Does anyone kn

ExtremeBDS [4]

Answer:

400 seconds

Step-by-step explanation:

150/20=7.5 meters per second

3000/7.5=400 seconds

3 0

2 years ago

GIVING BRAINLIEST what is 97 - 56 + 12

quester [9]

Answer:

Step-by-step explanation:

When subtracting 97-56=41+12=53. The answer is 53. Consider using a calculator or mental math next time rather than asking it as a question.

Hope this helps!!! PLZ MARK BRAINLIEST!!!

8 0

2 years ago

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How to solve logarithmic equations as such

Serga [27]

$\bf \textit{exponential form of a logarithm} \\\\ \log_a b=y \implies a^y= b\qquad\qquad a^y= b\implies \log_a b=y \\\\\\ \begin{array}{llll} \textit{Logarithm of exponentials} \\\\ \log_a\left( x^b \right)\implies b\cdot \log_a(x) \end{array} ~\hspace{7em} \begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad \stackrel{\textit{we'll use this one}}{a^{log_a x}=x} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf \log_2(x-1)=\log_8(x^3-2x^2-2x+5) \\\\\\ \log_2(x-1)=\log_{2^3}(x^3-2x^2-2x+5) \\\\\\ \log_{2^3}(x^3-2x^2-2x+5)=\log_2(x-1) \\\\\\ \stackrel{\textit{writing this in exponential notation}}{(2^3)^{\log_2(x-1)}=x^3-2x^2-2x+5}\implies (2)^{3\log_2(x-1)}=x^3-2x^2-2x+5$

$\bf (2)^{\log_2[(x-1)^3]}=x^3-2x^2-2x+5\implies \stackrel{\textit{using the cancellation rule}}{(x-1)^3=x^3-2x^2-2x+5} \\\\\\ \stackrel{\textit{expanding the left-side}}{x^3-3x^2+3x-1}=x^3-2x^2-2x+5\implies 0=x^2-5x+6 \\\\\\ 0=(x-3)(x-2)\implies x= \begin{cases} 3\\ 2 \end{cases}$

5 0

2 years ago