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Marizza181 [45]

2 years ago

8

If you have 2 pounds of grapes and there $6 how much is 1 pound grapes?

2 answers:

Vikki [24]2 years ago

7 0

Answer:

$3

Step-by-step explanation:

kotykmax [81]2 years ago

4 0

Answer:

3$

Step-by-step explanation:

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Given the equation below, solve for the variable t.<br><br> p+o−wt=4b

kotegsom [21]

P+o-wt=4b
-wt=4b-p-o
t=(4b-p-o)/-w

mark as brainliest if it’s helpful

8 0

2 years ago

12 divided by 100 as a mixed number or whole number

tamaranim1 [39]

12/100 = 3/25
hope it helps

5 0

3 years ago

I WILL GIVE BRAINLIEST

nydimaria [60]

Answer:

2+0.15x=3.20

Step-by-step explanation:

So you have the original or starting point $2 which b in y=Mx+b then it’s 0.15 per day but you don’t know how many days so you use x and she owed a total of 3.20

3 0

2 years ago

Vocabulary Choose the example of an inverse relationship.

natulia [17]

Answer:

which statement is equivalent to the inequality 14x-14>-7x+7

x>21

x>1

x<

x=1which statement is equivalent to the inequality 14x-14>-7x+7

x>21

x>1

x<

x=1which statement is equivalent to the inequality 14x-14>-7x+7

x>21

x>1

x<

x=1which statement is equivalent to the inequality 14x-14>-7x+7

x>21

x>1

x<

x=1which statement is equivalent to the inequality 14x-14>-7x+7

x>21

x>1

x<

x=1which statement is equivalent to the inequality 14x-14>-7x+7

x>21

x>1

x<

x=1which statement is equivalent to the inequality 14x-14>-7x+7

x>21

x>1

x<

x=1

4 0

2 years ago

Evaluate the function at the indicated values if possible. If an indicated value is not in the domain, say so.

goldfiish [28.3K]

Answer:

f(-7)=0.

f(2)=-9/5.

f(3) doesn't exist because 3 isn't in the domain of the function.

Step-by-step explanation:

$f(x)=\frac{x+7}{x^2-9}$ is the given function.

We are asked to find:

$f(-7)$

$f(2)$

$f(3)$ .

f(-7) means to replace x in the expression called f with -7:

Evaluate $\frac{x+7}{x^2-9}$ at $x=-7$

$\frac{(-7)+7}{(-7)^2-9}$

$\frac{0}{49-9}$

$\frac{0}{40}$

$0$

So f(-7)=0.

f(2) means to replace x in the expression called f with 2:

Evaluate $\frac{x+7}{x^2-9}$ at $x=2$

$\frac{2+7}{2^2-9}$

$\frac{9}{4-9}$

$\frac{9}{-5}$

$\frac{-9}{5}$

So f(2)=-9/5

f(3) means to replace x in the expression called f with 3:

Evaluate $\frac{x+7}{x^2-9}$ at $x=3$

$\frac{3+7}{3^2-9}$

$\frac{10}{9-9}$

$\frac{10}{0}$

Division by 0 is not allowed so 3 is not in the domain of our function.

5 0

2 years ago