Options:
A) Cells require much less P to grow than N, so extra P will be used for ATP synthesis and result in a faster growth rate.
B) Cells will never consume all of the phosphate, because N is needed in higher quantities than P.
C) The final biomass of cells will be no different than if only 50% of the phosphate was provided.
D) The bacteria will import all of the ammonia to use for biosynthetic pathways.
Answer:A) Cells require much less P to grow than N, so extra P will be used for ATP synthesis and result in a faster growth rate.
Explanation: Chemoorganoheterophic Bacteria are bacteria which requires the supply of organic nutrients of Carbon and metabolic energy. If Ammonia and potassium are provided at equal amount or concentration, the least likely occurrence will be that
Cells require much less P(potassium) to grow than N(Nitrogen), so extra P(potassium) will be used for ATP synthesis and result in a faster growth rate. This is so because Chemoorganoheterophic Bacteria requires organic supply of nutrients in the form of Carbon and metabolic energy.
Answer:
a animal cell it tiny little pieces in the animal bodies
Hi,
Attached is solution diagram. You can see that true breeding means both have same alleles for purple PP and white WW flowers.
They were crossed to produce hybrid plants that all had purple flowers PW because purple was the dominant trait.
However, upon self fertilization of those hybrid plants, both purple and white flower plants were produced in 3:1.
Hope it helps!