Ask question

Ask question

All categories

2 years ago

7

A 150 j of energy is added to a system that does 50 j of work is done. By how much wiull the internal energy of the system be ra

ised?

2 answers:

Alex73 [517]2 years ago

8 0

Answer:

<h2>3 internal energy</h2>

Explanation:

${hope it helps}}$

madam [21]2 years ago

6 0

Answer:

thnx for the points too muchee

Explanation:

You might be interested in

What two properties of a gas depend on its container

katrin [286]

uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuum i thinkitis the way its shaped

6 0

2 years ago

The initial pressure and volume of a gas are 55.16 kilopascals and 0.500 liter. According to Boyle’s law, if the volume of the g

Gnesinka [82]

Answer: The final pressure is 34.48kPa

Initial Pressure P1 = 55.16kPa

Initial Volume V1 = 0.500L

Final Pressure P2 = ?

Final Volume V2 = 0.800L

Boyle's law P1V1 = P2 V2

P2 = P1V1/V2

P2 = 55.16*0.5/0.8

P2 = 34.48kPa

7 0

2 years ago

The distance between the centers of the two oxygen atoms in an oxygen molecule is 1.21 x 10-8 cm. What is this distance in inche

Sergio [31]

Answer:

$d=4.75\times 10^{-9}\ \text{inches}$

Explanation:

Given that,

The distance between the centers of the two oxygen atoms in an oxygen molecule is $1.21\times 10^{-8}\ cm$ .

We need to convert this distance in inches.

We know that,

1 cm = 0.393 inches

We can solve it as follows :

$1.21\times 10^{-8}\ cm=0.393\times 1.21\times 10^{-8}\\\\=4.75\times 10^{-9}\ \text{inches}$

So, the distance between the centers of the two oxygen atoms is $4.75\times 10^{-9}\ \text{inches}$ .

5 0

2 years ago

Give two properties that glass and plastic sometimes share.

dmitriy555 [2]

Answer:

Wall, cup, mug, plastic spoon

Explanation:

Because all of those are glass and it is important to us to make sure that if you are touching this brle careful

8 0

2 years ago

Read 2 more answers

The standard enthalpy change for the following reaction is 232 kJ at 298 K. 2 H2CO(g) 2 C(s,graphite) + 2 H2(g) + O2(g) ΔH° = 23

Georgia [21]

Answer: The standard enthalpy change for this reaction is -116 kJ

Explanation:

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction is,

$2H_2CO(g)\rightarrow 2C(s, graphite)+2H_2(g)+O_2(g)$

$\Delta H^0=232KJ$

Now we have to determine the value of $\Delta H$ for the following reaction i.e,

$)C(s, graphite)+H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2CO(g)$ $\Delta H^0'=?$

According to the Hess’s law, if we reverse the reaction then the $\Delta H$ will change its sign and if we half the reaction, then the

So, the value $\Delta H^0'$ for the reaction will be:

$\Delta H^0'=\frac{(-232kJ/mole)}{2}=-116kJ$

Hence, the standard enthalpy change for this reaction is -116 kJ

7 0

3 years ago