The solution to the equation x(x+4) = 6 is x = -2 + √10 or x = -2 - √10 after solving with the quadratic formula.
<h3>What is a quadratic equation?</h3>
Any equation of the form where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic equation.
As we know, the formula for the roots of the quadratic equation is given by:
We have an equation:
x(x + 4) = 6
By distributive property:
x² + 4x = 6
x² + 4x - 6 = 0
a = 1, b = 4, c = -6
Plugging all the values in the formula:
After calculating:
Thus, the solution to the equation x(x+4) = 6 is x = -2 + √10 or x = -2 - √10 after solving with the quadratic formula.
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Answer:
We know that:
Energy released by fusion of hydrogen in 1 liter of solution A = 7.6x10^10 J
Energy used daily in a certain family home = 3x10^4 J
(you did not write the units, so i suppose that are the same in both cases)
Then, if x is the number of liters of solution A used, the energy produced will be:
E(x) = x*7.6x10^10 J
And we want this equal to 3x10^4
then:
E(x) = x*7.6x10^10 J = 3x10^4 j
now we solve this for x.
x = (3x10^4 j)/(7.6x10^10 j) = 3.9x10^-7
Then you need to use 3.9x10^-7 L of solution a.
Answer:
Graphed?
Step-by-step explanation:
Answer:
Option C: n = 32; p^ = 0.4
Step-by-step explanation:
The normal curve can be used in this case if; np ≥ 10 or n(1 - p) ≥ 10
A) For n = 28 and p = 0.3;
np = 28 × 0.3 = 8.4 < 10
Thus, it can't be used.
B) For n = 28 and p = 0.9;
np = 28 × 0.9 = 25.2 > 10 Ok
n(1 - p) = 28(1 - 0.9) = 2.8 Not Ok
Thus, it can't be used
C) For n = 32 and p = 0.4
np = 32 × 0.4 = 12.8 > 10 Ok
n(1 - p) = 32(1 - 0.4) = 19.2 > 10 Ok
Thus, it can be used
D) For n = 32 and p = 0.2
np = 32 × 0.2 = 6.4 < 10 Not Ok
Thus it can't be used.