Answer:
40
Step-by-step explanation:
(2x+1/(2x))^5 *(2x -1/(2x))^5
= ((2x)^2 -1/(2x)^2)^5 (a+b)*(a-b) =a2-b2
= (4x^2-1/4(x)^2)^5
now
x =4x^2. ,a = 1/4(x)^2 ,n =5
we have
general term = Cr *x^r *a^(n-r)
= Cr * (4x^2)^r * (1/4(x)^2)^(n-r)
= Cr *4^r * X^2r * 1/( 4^(n-r) *x^(2n-2r)
= Cr * 4^r/4^(n-r) * x^(2r)/x^(2n-2r)
= Cr * 4(2r-n) *x(4r-2n)
now for x^2
4r-2n = 2
4r -10=2
4r =12
r = 3
now for coeff
C(5,3) * 4^(2*3-5)
5!/(3!*(5-3)!) * 4
5*4/(2*1)*4
40
Answer:
x⁴ + 6x² + 9
Explanation:
To answer this question, we will multiply each term from the first bracket by each term from the second bracket and then combine like terms to get the final expression.
This can be done as follows:
(x² + 3)(x² + 3)
x²(x²) + x²(3) + 3(x²) + 3(3)
x⁴ + 3x² + 3x² + 9
x⁴ + 6x² + 9
Hope this helps :)
Answer:
x=-4
x=4
Step-by-step explanation:
We can factor x^2 -16 = 0 by recognizing that it is a difference of squares. That means we can factor the equation to (x-4)(x+4) = 0. By using the Zero Product Property we know that either (x-4) or (x+4) is equal to 0. That means that x either equals -4 or 4.
Answer:
<u>domain: {10,15,19,32}</u>
<u>range:{5,9,-1}</u>
Step-by-step explanation:
- As we know domain is the values of input and range is the values of output.
- Here , x is the input and y is the output.
- Thus the input values according to the given problem is : 10 ,15 , 19, and thus ,
⇒<em>The domain would accordingly be these four numbers : 10 , 15 , 19 , 32.</em>
- <u>Note that we donot have any information regarding the other values of x.</u>
- The range is : { 5,9,-1 } only as the 5 is repeated in two cases .
- Range is unique and there must be not repetition. Thus the apt answer would be :
<em>domain: {10,15,19,32}</em>
<em>range:{5,9,-1}</em>
Answer: 749,250
Step-by-step explanation:
700,000 + 40,000= 740,000.
9,000+200+50= 9,250.
740,000 + 9,250 = 740,250.