The correct option is option A: Trial 1, because the average rate of the reaction is lower
<em>The average rate of reaction increases as the concentration of reactants increases;</em>
The rate of reaction increases as the concentration of reactants increases because the number moles of the reaction particles increases resulting in increased collisions among the reacting particles followed by an increase in the number of effective collisions to form the total possible number of the product at a shorter time which shows a higher reaction rate.
The higher the reaction rate, the steeper the slope of the graph of the Amount of Products to Time produced and, from the given graph, Trial 2 has a higher average rate of reaction and given that other factors were kept constant, a higher concentration of reaction, while, Trial 1 that has a gentler slope of Amount of Product to Time has a lower concentration of the reactant, and therefore, the average rate of reaction in Trial 1, is lower
Therefore, the statement that explains which trial has a lower concentration of the reactant is option A, Trial 1, because the average rate of the reaction is lower