The distance covered will be 0.301m.
firstly we will new to calculate acceleration (a).
we can do so using newtons first law of motion.
v=u + a × t
where
a is the acceleration
t is the time
from here we get
a=(v-u)/t
a=(4-0)/0.15
a=26.67m/s²
using newtons second law of motion
s=u.t+1/2at²
where s is distance travelled in t seconds.
we get,
s=0.301m
learn more about newtons law of motion here:
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I would use meter and second.
Hope this helps.
Answer:
The velocity & acceleration will be taken as negative when a ball is thrown upward because work is done against the gravity.
Explanation:
Answer:
Physics
Explanation:
Explanation:
We can use the Theorem of Work (W) and Kinetic Energy (K):
W=ΔK=Kf−Ki
it basically tells us that the work done on our system will show up as change in Kinetic Energy:
We know that the initial Kinetic Energy, Ki=12mv2i, is zero (starting from rest) while the final will be equal to 352J; Work will be force time displacement. so we get:
F⋅d=Ff
45d=352
and so:
d=35245=7.8≈8m
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