Answer:
a) Vf = 27.13 m/s
b) It would have been the same
Explanation:
On the y-axis:
Solving for t:
t1 = 0.67s t2= -2.4s
Discarding the negative value and using the positive one to calculate the velocity:
So, the module of the velocity will be:
If you throw it above horizontal, it would go up first, and when it reached the initial height, the velocity would be the same at the throwing instant. And starting then, the movement will be the same.
I would say B. hope it helps
Answer:
the magnitude of the electric field is 1.25 N/C
Explanation:
The induced emf in the cube ε = LB.v where B = magnitude of electric field = 5 T , L = length of side of cube = 1 cm = 0.01 m and v = velocity of cube = 1 m/s
ε = LB.v = 0.01 m × 5 T × 1 m/s = 0.05 V
Also, induced emf in the cube ε = ∫E.ds around the loop of the cube where E = electric field in metal cube
ε = ∫E.ds
ε = Eds since E is always parallel to the side of the cube
= E∫ds ∫ds = 4L since we have 4 sides
= E(4L)
= 4EL
So,4EL = 0.05 V
E = 0.05 V/4L
= 0.05 V/(4 × 0.01 m)
= 0.05 V/0.04 m
= 1.25 V/m
= 1.25 N/C
So, the magnitude of the electric field is 1.25 N/C
Answer: C
Explanation:
A collision in which the objects stick together is sometimes called “perfectly inelastic“
The correct option is D.
Micheal Friday devised a wire which hanged down into a glass vessel that has a bar magnet secured at the bottom. He then filled the glass vessel with Mercury and connected the apparatus to a battery. This sent electricity through the wire, thus creating a magnetic field around it. This field interacted with the field around the magnet and cause the wire to rotate clock wisely.
