Well, let's see. The problem gave you an ordered pair. In other words, you have an 'x' and a 'y' coordinate. All you need to do is put them into the equation.
Step-by-step explanation:
This means that instead of --
-3x - 3y = 125 + 5y = -20
We would have:
-3(-5)-3(-5) = 125(-5) + 5(-5) = -20
From here, you just simplify it into:
30 = -650 = -20
Since the values are not the same, the ANSWER is NO. The ordered pair does not satisfy the following system of equations.
Answer:
a.) Between 0.5 and 3 seconds.
Step-by-step explanation:
So I just went ahead and graphed this quadratic on Desmos so you could have an idea of what this looks like. A negative quadratic, and we're trying to find when the graph's y-values are greater than 26.
If you look at the graph, you can easily see that the quadratic crosses y = 26 at x-values 0.5 and 3. And, you can see that the quadratic's graph is actually above y = 26 between these two values, 0.5 and 3.
Because we know that the quadratic's graph models the projectile's motion, we can conclude that the projectile will also be above 26 feet between 0.5 and 3 seconds.
So, the answer is a.) between 0.5 and 3 seconds.
Answer:
8 pieces of string
Step-by-step explanation:
Given that :
Total yards of string = 4
Length in yd of each string = 1/2 yards
Number of pieces of string Ms. Cole has :
Total. Yards / length in yard of each string
4 / (1/2)
4 * (2 /1)
= 8/1
= 8 pieces of string.
Answer:
79.5 + 5.5x = Y
Step-by-step explanation:
Sumo wrestler gained 5.5 kg per month
After 11 month, he weighed 140 kg.
Let x be his current weight.
Then x + 11(5.5) = 140
x = 140 - 60.5
x = 79.5
If Y is the weight of the wrestler after t months, then the linear equation would be:
79.5 + 5.5t = Y
