Let a=price of adult ticket
let c=price of a child's ticket
start out by writing the following system of equations:
3a+4c=132
2a+3c=94
then, multiply the first equation by 2, and the second equation by 3 to get the following system of equations:
6a+8c=264
6a+9c=282
subtract the like terms to get the following equation:
-c=-18
divide both sides by -1 to get rid of the negative to get the price of a child's ticket to be $18. to find the price of an adult ticket, pick one of the original equations to substitute the 18 in for c to find a. for example:
2a+3c=94
2a+3(18)=94
2a+54=94
-54 -54
2a=40
2 2
a=20
or if you decide to use the other equation:
3a+4c=132
3a+4(18)=132
3a+72=132
-72 -72
3a=60
3 3
a=20
either way, you still get an adults ticket to be $20 and a child's ticket to be $18.
Answer:
i think it's B 3.46
Step-by-step explanation:
hope this helps
Answer:
B
Step-by-step explanation:
Using the expansion
tan(x - y) = 
, then
tan(x - 
)
= 
note that tan( -) = - tan() = - 
= 
= 
→ B
Step-by-step explanation:
Answer:
She bought 24 Tangram puzzles
Step-by-step explanation:
Let the number of Tangram puzzles be t and the number of IQ puzzles be i
The sum of all the puzzles is 40;
i + t = 40 ••••••(i)
Cost of all Tangram puzzles at a cost of $4 per one will be;
4 * t = $4t
cost of all Iq puzzles at a cost of $2 per one is
2 * i = $2i
Sum
paid for all is $128
so;
4t + 2i = 128 •••••••(ii)
From equation i;
i = 40-t
Substitute into ii
4t + 2(40-t) = 128
4t + 80 - 2t = 128
2t = 128-80
2t = 48
t = 48/2
t = 24
