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2 years ago

What is 19% as a decimal and a fraction?

Mathematics

2 answers:

kondaur [170]2 years ago

6 0

Answer:

Decimal - 0.19 Fraction - 19/100

Step-by-step explanation:

melisa1 [442]2 years ago

6 0

Answer:

Decimal: 0.19

Fraction: 19/100

Step-by-step explanation:

19% means that there is 19/100 which is also 0.19 as a decimal. I dont really know how to explain this but can you please mark as brainliest?

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What does it mean for two fractions to be equivalent? For two ratios to be equivalent?

poizon [28]

Answer:

Equivalent fractions and ratios mean that when simplified, they are the same one fraction or ratio. see examples below.

Step-by-step explanation:

For example, the fraction 1/2 is the same as 2/4 or 15/30 because when you simplify them, they are still 1/2. Therefore they are equivalent.

For example, the ratio 1:2 is the same as 5:10 or 10:20 since when broken down they all come down to 1:2. Hence they are equivalent.

Hope this answers your question.

3 0

2 years ago

0.06 or 0.06666666666 As a fraction

garik1379 [7]

0.06 = 6/100
When simplified, that's 3/50 .

0.06666666666 = 6,666,666,666/10,000,000,000
When simplified, that's 3,333,333,333/5,000,000,000 .

8 0

2 years ago

Solve the equation A = bh for b. b = Ah b = A/h b = h/A b = h – A Solve the equation A = bh for b. b = Ah b = A/h b = h/A b = h

Leto [7]

Answer:

The answer is " $b=\frac{A}{h}$ ".

Step-by-step explanation:

Therefore in this question the "bh" were the multiplied and these values includes the variable which is solving by the isolating of "b".

Let's Divides the both sides for h.

$\to \frac{A}{h} = \frac{bh}{h}\\\\\to \frac{A}{h} = b\\\\\to b= \frac{A}{h}$

7 0

2 years ago

If x = 4 and y = 7 , evaluate the following expression: 100 − 3 ( 3 y − 4 x

ivolga24 [154]

Answer:

100-3*3*7-4*4

97*21-16

97*5

=455

3 0

2 years ago

Read 2 more answers

Find an equation of the tangent plane to the given parametric surface at the specified point.

Neko [114]

Answer:

Equation of tangent plane to given parametric equation is:

$\frac{\sqrt{3}}{2}x-\frac{1}{2}y+z=\frac{\pi}{3}$

Step-by-step explanation:

Given equation

$r(u, v)=u cos (v)\hat{i}+u sin (v)\hat{j}+v\hat{k}$ ---(1)

Normal vector tangent to plane is:

$\hat{n} = \hat{r_{u}} \times \hat{r_{v}}\\r_{u}=\frac{\partial r}{\partial u}\\r_{v}=\frac{\partial r}{\partial v}$

$\frac{\partial r}{\partial u} =cos(v)\hat{i}+sin(v)\hat{j}\\\frac{\partial r}{\partial v}=-usin(v)\hat{i}+u cos(v)\hat{j}+\hat{k}$

Normal vector tangent to plane is given by:

$r_{u} \times r_{v} =det\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\cos(v)&sin(v)&0\\-usin(v)&ucos(v)&1\end{array}\right]$

Expanding with first row

$\hat{n} = \hat{i} \begin{vmatrix} sin(v)&0\\ucos(v) &1\end{vmatrix}- \hat{j} \begin{vmatrix} cos(v)&0\\-usin(v) &1\end{vmatrix}+\hat{k} \begin{vmatrix} cos(v)&sin(v)\\-usin(v) &ucos(v)\end{vmatrix}\\\hat{n}=sin(v)\hat{i}-cos(v)\hat{j}+u(cos^{2}v+sin^{2}v)\hat{k}\\\hat{n}=sin(v)\hat{i}-cos(v)\hat{j}+u\hat{k}\\$

at u=5, v =π/3

$=\frac{\sqrt{3} }{2}\hat{i}-\frac{1}{2}\hat{j}+\hat{k}$ ---(2)

at u=5, v =π/3 (1) becomes,

$r(5, \frac{\pi}{3})=5 cos (\frac{\pi}{3})\hat{i}+5sin (\frac{\pi}{3})\hat{j}+\frac{\pi}{3}\hat{k}$

$r(5, \frac{\pi}{3})=5(\frac{1}{2})\hat{i}+5 (\frac{\sqrt{3}}{2})\hat{j}+\frac{\pi}{3}\hat{k}$

$r(5, \frac{\pi}{3})=\frac{5}{2}\hat{i}+(\frac{5\sqrt{3}}{2})\hat{j}+\frac{\pi}{3}\hat{k}$

From above eq coordinates of r₀ can be found as:

$r_{o}=(\frac{5}{2},\frac{5\sqrt{3}}{2},\frac{\pi}{3})$

From (2) coordinates of normal vector can be found as

$n=(\frac{\sqrt{3} }{2},-\frac{1}{2},1)$

Equation of tangent line can be found as:

$(\hat{r}-\hat{r_{o}}).\hat{n}=0\\((x-\frac{5}{2})\hat{i}+(y-\frac{5\sqrt{3}}{2})\hat{j}+(z-\frac{\pi}{3})\hat{k})(\frac{\sqrt{3} }{2}\hat{i}-\frac{1}{2}\hat{j}+\hat{k})=0\\\frac{\sqrt{3}}{2}x-\frac{5\sqrt{3}}{4}-\frac{1}{2}y+\frac{5\sqrt{3}}{4}+z-\frac{\pi}{3}=0\\\frac{\sqrt{3}}{2}x-\frac{1}{2}y+z=\frac{\pi}{3}$

5 0

2 years ago