Elavter of using distuburting propties a. 17×102 b. 477×1035 -477×35
1 answer:
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Answer:
line c
Step-by-step explanation:
The graph representing a direct variation equation always passes through the origin. This could be graphs (a) or (c)
given y = x
with slope =
Since graph (a) slopes down from left to right it's slope is negative
Hence it is not graph (a) as the slope given in the equation is positive.
Hence the required graph is (c)
The complete question in the attached figure
we know that
the equation of a parabola is
y=a(x-h)²+k
where
(h,k) is the vertex --------> (h,k)--------> (-1,2)
so
y=a(x+1)²+2
point (2,20)
for x=2
y=20
20=a(2+1)²+2--------> 20=a*9+2--------> 9*a=18---------> a=2
the equation of a parabola is
y=a(x+1)²+2-------> y=2(x+1)²+2
therefore
the answer is the option
<span>C) f(x) = 2(x + 1)2 + 2</span>
we know that
the equation of a parabola is
y=a(x-h)²+k
where
(h,k) is the vertex --------> (h,k)--------> (-1,2)
so
y=a(x+1)²+2
point (2,20)
for x=2
y=20
20=a(2+1)²+2--------> 20=a*9+2--------> 9*a=18---------> a=2
the equation of a parabola is
y=a(x+1)²+2-------> y=2(x+1)²+2
therefore
the answer is the option
<span>C) f(x) = 2(x + 1)2 + 2</span>