From the Arithmetic Information given, Pr = 0.049375 ≠ -8.050625 ≠ 0.0325 See explanation below.
<h3>
What are the step by steps solution to the questions above?</h3>
First, lets us restate the question properly. We have
Pr = 1 - ((6*12+6)/80)² = 1 - ((9*12²)/1600) - ((3*12*6)/1600) - (6²/6400) = 1 - 0.005625 * 12² - 0.001875 * 12 * 6 - 0.00015625 * 6²
Note that there are three equals signs. So lets divide the problem according and solve for the different parts.
Lets 1 - ((6*12+6)/80)² ............A
1 - ((9*12²)/1600) - ((3*12*6)/1600) - (6²/6400) .............B; and
1 - 0.005625 * 12² - 0.001875 * 12 * 6 - 0.00015625 * 6² ........C
Solving for A we have
1 - (78/80)²
= 1 - (0.975)²
= 1 - 0.950625
A = 0.049375
Solving for B we have
1 - ((9*12²)/1600) - ((3*12*6)/1600) - (6²/6400)
= 1- (14,256/1600) - (216/1600) - (36/6400)
= 1 - 8.91 - 0.135 - 0.005625
B = -8.050625
Solving for C we have
1 - 0.005625 * 12² - 0.001875 * 12 * 6 - 0.00015625 * 6²
= 1 - 0.005625 * 144 - 0.001875 * 12 * 6 - 0.00015625 * 144
= 0.0325
In summary we can state that:
A = 0.049375
B = -8.050625
C = 0.0325
Given that there were no abstract quantities, we can state that
Pr = A ≠ B ≠C or
Pr = 0.049375 ≠ -8.050625 ≠ 0.0325
Learn more about equations with equal signs at
brainly.com/question/18924248
#SPJ1
In the fairest school 70% are below 16 years old
1/3 are teachers which is equals to = 21
Let’s start solving:
=> 1/3 of 100%
=> 100 / 3 = 33.33%
thus 33.33% = 21
=> 21 x 3 = 63, is the total number of people in the school.
Let’s try solving the number of people below 16 years old
Have you notice that you are asking for a 70% of students but there are already 33.33% of teacher. Thus your given problem is not right already.
=> 100% - 33.33% = 66.67% that’s the only remaining percentage and not 70%
=> 63 * .6667 = 42.0021
Thus, there are around 42 people who are 16 years old younger.
8 is 1/6 of 8/6 = 1 1/3
125 is 5/10 of 625/10 = 62 1/2
32 is 4/10 of 128/10 = 12 4/5